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valkas [14]
3 years ago
5

An A-frame house is 45 feet high and 32 feet wide. Find the measure of the angle that the roof makes with the floor. Round to th

e nearest degree.

Mathematics
1 answer:
Flura [38]3 years ago
4 0

Answer:

Angle, \theta=70.4^{\circ}

Step-by-step explanation:

We have, an A-frame house is 45 feet high and 32 feet wide. It is required to find the measure of the angle that the roof makes with the floor.

The attached figure shows the A frame. Let \theta is the angle that the roof makes with the floor. So,

\tan\theta=\dfrac{45}{16}\\\\\tan\theta=2.81\\\\\theta=\tan^{-1}(2.81)\\\\\theta=70.4^{\circ}

So, the angle of 70.4 degrees is the angle that the roof makes with the floor.

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Cuboid ABCDEFGH is shown
gtnhenbr [62]

Answer:

The angle formed between CF and the plane ABCD is approximately 47.14°

Step-by-step explanation:

The given parameters are;

BC = 6.8

DE = 9.3

∠BAC = 52°

We note that the angles formed by the vertex of a cuboid are right triangles, therefore, by trigonometric ratios, we get;

sin∠BAC = BC/(The length of a line drawn from A to C)

∴ The length of the line drawn from A to C = BC/sin∠BAC

The length of the line drawn from A to C = 6.8/sin(52°) ≈ 8.63

∴ AC = 8.63

By trigonometry, we have;

The angle formed between CF and the plane ABCD = Angle ∠ACF

tan\angle X = \dfrac{Opposite \ leg \ length}{Adjacent\ leg \ length}

tan\angle ACF = \dfrac{FA}{AC}

In a cuboid, FA = BG = CH = DE = 9.3

\therefore tan\angle ACF = \dfrac{9.3}{8.63}

\therefore \angle ACF = arctan \left(\dfrac{9.3}{8.63} \right) \approx 47.14^{\circ}

The angle formed between CF and the plane ABCD = Angle ∠ACF ≈ 47.14°

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