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valkas [14]
3 years ago
5

An A-frame house is 45 feet high and 32 feet wide. Find the measure of the angle that the roof makes with the floor. Round to th

e nearest degree.

Mathematics
1 answer:
Flura [38]3 years ago
4 0

Answer:

Angle, \theta=70.4^{\circ}

Step-by-step explanation:

We have, an A-frame house is 45 feet high and 32 feet wide. It is required to find the measure of the angle that the roof makes with the floor.

The attached figure shows the A frame. Let \theta is the angle that the roof makes with the floor. So,

\tan\theta=\dfrac{45}{16}\\\\\tan\theta=2.81\\\\\theta=\tan^{-1}(2.81)\\\\\theta=70.4^{\circ}

So, the angle of 70.4 degrees is the angle that the roof makes with the floor.

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The bottom layer of a rectangular prism contains 15 unit cubes The prism is made up of 5 equal-size layers what is the volume of
borishaifa [10]

Answer:

75 cubic units

Step-by-step explanation:

Bottom layer of a rectangular prism is made up of 15 unit cubes.

Therefore, area of the 15 unit cubes = 15(area of the base of one unit cube)

                                                            = 15(1)²

                                                            = 15 unit²

Number of layers of unit cubes in the rectangular prism = 5

So the height of the prism = 5 units

Volume of the prism = (Area of the base) × Height

                                  = 15 × 5

                                  = 75 cubic unit

6 0
3 years ago
30 treadmills to 36 elliptical machines the ratio in simplest form
Goshia [24]
30 treadmills : 36 ellipticals
this could be written in a few ways, but i am going to write it as a fraction. since treadmills come first, you put 30/36.

now that you have your fraction you have to find the GCF (greatest common factor) of the two numbers. the GCF is 6, so you have to divide 30 treadmills by 6, and 36 ellipticals by 6.
30/6=5
36/6=6

5/6 or 5:6 is the simplified ratio of treadmills to ellipticals



comment for any questions!!
4 0
4 years ago
Find the distance between the complex numbers. z1 = 9 - 9i z2 = 10 - 9i
steposvetlana [31]

Answer:

The distance between the two given complex numbers = 9

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i):</em></u>-

Given  Z₁ = 9 - 9 i    and Z₂ = 10 -9 i

Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane

⇒ A =  Z₁ = x₁ +i y₁ = 9 - 9 i and

    B = Z₂ = x₂+ i y₂ = 10 -9 i

Let (x₁ , y₁) = ( 9, -9)

     (x₂, y₂) = (10, -9)

<u>Step(ii)</u>:-

<em>The distance between the two points are </em>

    A B   =   \sqrt{(x_{2} - x_{1})^{2}+(y_{2} - y_{1})^{2}    }

    A B =   \sqrt{(10 - 1)^{2}+(-9 - (-9))^{2}    }

   AB   = \sqrt{(9)^{2} +(-9+9)^{2} }

 <em> AB    =  √81 = 9</em>

<u><em>Conclusion:-</em></u>

The distance between the two given complex numbers = 9

<u><em></em></u>

3 0
3 years ago
On a number line, what is the unit distance between –11 and 3?
kumpel [21]
The answer is 14

explanation answer: 14
3 0
3 years ago
Read 2 more answers
Given f(x) = 10 - 16/x, find all c in the interval [2,8] that satisfy the mean value theorem
Katen [24]
F(x)=10-16/x
f'(x)=16/x^2
f'(c)=16/c^2
f(8)=10-16/8=10-2=8
f(2)=10-16/2=10-8=2
f'(c)= \frac{f(b)-f(a)}{b-a} in (2,8),&#10; \frac{16}{c^2} = \frac{f(8)-f(2)}{8-2} ,&#10; \frac{16}{c^2} = \frac{8-2}{8-2}&#10;
4∈[2,8] is the required point.
8 0
4 years ago
Read 2 more answers
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