The containers must be spheres of radius = 6.2cm
<h3>
How to minimize the surface area for the containers?</h3>
We know that the shape that minimizes the area for a fixed volume is the sphere.
Here, we want to get spheres of a volume of 1 liter. Where:
1 L = 1000 cm³
And remember that the volume of a sphere of radius R is:

Then we must solve:
![V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{ (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%2A3.14%2AR%5E3%20%3D%201000cm%5E3%5C%5C%5C%5CR%20%3D%5Csqrt%5B3%5D%7B%20%20%281000cm%5E3%2A%5Cfrac%7B3%7D%7B4%2A3.14%7D%20%29%7D%20%3D%206.2cm)
The containers must be spheres of radius = 6.2cm
If you want to learn more about volume:
brainly.com/question/1972490
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404 is the answer. if you add them all together
Answer: the bridge is 11.025 m high
Step-by-step explanation:
Given that;
Time taken to hit the water t = 1.5 sec
height of bridge = ?
lets take a look at the equation of motion;
y(t) = y₀ + (1/2)at²
with initial velocity zero and we know that acceleration due to gravidity is 9.8m/s
we substitute
y(t) = (1/2)gt² = (1/2) × 9.8 × (1.5)²
y(t) = (1/2)gt² = (1/2) × 9.8 × (1.5)²
y(1.5) = 11.025 m
Therefore, the bridge is 11.025 m high
Your answer is C If not A have a good day
1 yard is 3 feet
1 foot is 12 inches
Convert everything into inches:
9 x 12 = 108 in.
6 x 3 = 18 ft.
18 x 12 = 216
Add the inches together:
108 + 216 = 324 in
Multiply the inches by 2:
324 x 2 = 648 in
The answer is 648 inches.