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svlad2 [7]
3 years ago
14

Suppose medical records indicate that

Mathematics
1 answer:
Kay [80]3 years ago
3 0

Answer:

Step-by-step explanation:

Let x be the random variable representing the the length of newborn babies (in inches). Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

From the information given,

µ = 20 inches

σ = 2.6 inches

the probability that a given infant is between 14.8 and 25.2 inches long is expressed as

P(14.8 ≤ x ≤ 25.2)

For x = 14.8,

z = (14.8 - 20)/2.6 = - 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.023

For x = 25.2

z = (25.2 - 20)/2.6 = 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.98

Therefore,

P(14.8 ≤ x ≤ 25.2) = 0.98 - 0.23 = 0.75

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CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU.
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13/20

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Help asap my last question GIVING BRAINLIST!!!!
Alex

Answer:

1) x < 0

2) x > 0

3) x < 10

4) x < -\frac{31}{55}

5) x \geq 0

6) x \geq -1

Step-by-step explanation:

1) -3 > 2x -3

2x- 3 < -3

2x - 3 + 3 < -3 +3

2x < 0

\frac{2x}{2} < \frac{0}{2}

x < 0

2) 5 > -x + 5

-x + 5 < 5

- x + 5 -5 < 5 - 5

-x < 0

\frac{-x}{-1} < \frac{0}{-1}

x > 0

3) \frac{x}{5} -2 < 0

5 \times (\frac{x}{5} - 2 ) \times 5 < 0

x - 10 < 0

x -10 + 10 < 0 +10

x < 10

4) -5x + 11 > 31

-5x \cdot 11 < 31

-55x < 31

\frac{-55x}{-55} > \frac{31}{-55}

x < -\frac{31}{55}

5) \frac{1}{2}x - 4 \geq -4

\frac{1}{2}x -4 +4 \geq -4 +4

\frac{1}{2}x \geq 0

\frac{\frac{1}{2}x }{\frac{1}{2} } \geq \frac{0}{\frac{1}{2} }

x \geq 0

6) -4x + 2 \leq 6

-4x +2 - 2 \leq 6 -2

-4x < 4

\frac{-4x}{-4} \leq  \frac{4}{-4}

x \geq -1

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3 years ago
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