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r-ruslan [8.4K]
3 years ago
6

What are the zeros of the function? h(x)=x3−2x2−3x Select each correct answer.

Mathematics
1 answer:
Nat2105 [25]3 years ago
8 0
Hello again!

It looks like you need a lot of help today. I'm glad I am able to help you!

h(x) = x³ - 2x² - 3x

The question you need to ask yourself is "How do you find the zeros of a function.

Answer: To find the zeros of a function, just set the function equal to zero then solve for x

x³ - 2x² - 3x = 0

Factor the left sides

x(x + 1)(x - 3) = 0

Now we can set factors equal to 0

x = 0 or x + 1 = 0 or x - 3 = 0

x = 0 or x = 0 - 1 or x = 0 + 3

x = 0 or x = -1 or x = 3

Thus,

The zeros of the function are: x = 0 or x = -1 or x = 3

As always, I am glad to help students like you!
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We are given

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Firstly, we simplify left side

Left side is

((2x^9)(y^n))((4x^2)(y^{10}))

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and y terms together

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we can multiply left side by using exponent rule

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now, we can set them equal

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so, exponent of y must also be equal

we get

n+10=20

n=10................Answer



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