Answer:
Where is the chart???.....
Step-by-step explanation:
It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
X=3
Step-by-step explanation:
Subtract 3 from both sides
Simplify 27-3 to 24
Divide both sides by 8
Simplify 24/8 to 3
Answer:
True ( A )
Step-by-step explanation:
4 ( 5 ) - 2 = 2 ( 5 ) + 8
20 - 2 = 10 + 8
18 = 18
This is a correct statement because 18 does equal 18
60 minutes in an hour
60 x 8 = 480
his class is 480 minutes long
