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Gekata [30.6K]
3 years ago
10

The GCF of 48m3n2 and 80m5n.

Mathematics
1 answer:
kolbaska11 [484]3 years ago
3 0

Answer:

Step-by-step explanation:start like this:

48m3n2=2×2×2×2×3×m×m×m×n×n

80m5n=2×2×2×2×5×m×m×m×m×m×n

G.C.F=2×2×2×2×m×m×m×n

=16m3n

=16m^3n

Hope it helps you!!

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The vertices of a hyperbola are located at (−4, 1) and (4, 1). The foci of the same hyperbola are located at (−5, 1) and (5, 1).
topjm [15]

Answer:

x^2\ 16 - y^2/9 = 1

step-by-step explanation:

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it helps to graph this so you can see it better

to find a it is the distance from the center to the vertices which is 4 so in the equation you will write 16 becuase it is a^2

then you need to find b. to get b you have to figure out that c is the distance from the center to the foci which is 5 and it is all related to the plythagorm theorum becuase it forms a right triangle. so you do c^2 - a^2 = b^2

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3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:


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