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3 years ago

The GCF of 48m3n2 and 80m5n.

Mathematics

1 answer:

kolbaska11 [484]3 years ago

3 0

Answer:

Step-by-step explanation:start like this:

48m3n2=2×2×2×2×3×m×m×m×n×n

80m5n=2×2×2×2×5×m×m×m×m×m×n

G.C.F=2×2×2×2×m×m×m×n

=16m3n

=16m^3n

Hope it helps you!!

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One vegetable warehouse had 210 tons of potatoes, another one has 180 tons. 90 tons of potatoes were delivered to the first and

amid [387]

Answer:

6days

Step-by-step explanation

Let's make an equation from this expression.

From the number of potatoes at the first warehouse after x days is:

y = 210 + 90x .............. 1

From the number of potatoes at the second warehouse after x days is:

y = 180 + 120x .............. 2

First warehouse having 1.2times

y = ( 210 + 90x ) × 1.2

y = 252 +108x ................... 3

Now, equate 2 and 3

252 + 108x = 180 + 120x

252 - 180 = 120x - 108x

72 = 12x

x = 72/12

x = 6

Now, substitute 6 into equation 1 and 2

From 1 , y = 210 + 90x

y = 210 + 90 ×6

y = 210 + 540

y = 750

From equation 2

y = 180 + 120x

y = 180 + 120×6

y = 180 + 720

y = 900

Recall that equation 1 was to be 1.2times

From the answer in equation 1

y =750

y = 750 × 1.2

y = 900

Hence, the answer is correct.

7 0

3 years ago

Read 2 more answers

Tu has a midpoint at M(0,2) . point T is at (0,3) . Find the coordinates of point U.

Ne4ueva [31]

The answer will be/is 0,1

8 0

3 years ago

The sum of three fourths of the number a<br> and 24 is negative 9. What is the value of a?

Sindrei [870]

Answer:

-44

Step-by-step explanation:

3/4 a+24=-9

3/4 a=-9-24

3/4a=-33

multiply by 4

3a=-132

a=-132/3=-44

8 0

4 years ago

Find the 30th term in the sequence: 18,15,12

r-ruslan [8.4K]

Since it is going down a constant rate (-3) keep subtracting 3 until you get to the 30th term.

8 0

3 years ago

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A car insurance company has determined that 9% of all drivers were involved in a car accident last year. among 14 drivers living

andriy [413]

The probability of getting 3 or more who were involved in a car accident last year is 0.126.

Given 9% of the drivers were involved in a car accident last year.

We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.

We have to use binomial theorem which is as under:

n $C_{r}p^{r} (1-p)^{n-r}$

where p is the probability an r is the number of trials.

Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]

=1-{ $14C_{0}0.9^{0} (0.1)^{14} +14C_{1} (0.9)^{1} (0.1)^{13} +14C_{2} (0.9)^{2} (0.1)^{12}$ }

=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}

=1-{0.2670+0.3654+0.2358}

=1-0.8682

=0.1318

Among the options given the nearest is 0.126.

Hence the probability that 3 or more are involved in the accident is 0.126.

Learn more about probability at brainly.com/question/24756209

#SPJ4

7 0

2 years ago