Let the three numbers be x, y, and z.
If the sum of the three numbers is 3, then x+y+z=3
If subtracting the second number from the sum of the first and third numbers gives 9, then x+z-y=9
If subtracting the third number from the sum of the first and second numbers gives -5, then x+y-z=-5
This forms the system of equations:
[1] x+y+z=3
[2] x-y+z=9
[3] x+y-z=-5
First, to find y, let's take do [1]-[2]:
x+y+z=3
-x+y-z=-9
2y=-6
y=-3
Then, to find z, let's do [1]-[3]:
x+y+z=3
-x+-y+z=5
2z=8
z=4
Now that you have y and z, plug them into [1] to find x:
x+y+z=3
x-3+4=3
x=2
So the three numbers are 2,-3, and 4.
Answer:
Step-by-step explanation:
Method 1:
Arithmetic sequence is in the form
d is the common difference, can be found by:
Subtituting the 
and 
You get:
Method 2 (Mathematical induction):
Assume it is in form
Base step: 
Inducive hypophesis:
GIven: 
Proved by mathematical induction
1.3y +3.2 = 1.3y +3.2
we notice that both sides of the equation are identical. So substitute y with any value and the equation would still be correct.
y has infinite solutions.
Answer:
The maximum will be 78
Step-by-step explanation:
