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2 years ago

6

I made 2 calls and was on the phone for a total of 46 minutes. One call was 10 mins. longer than the other. How long was each c

all?

2 answers:

wlad13 [49]2 years ago

7 0

The one call that was ten min more is 56 min

sleet_krkn [62]2 years ago

5 0

Answer:

you spent 56 mins.

Step-by-step explanation:

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At the sixth grade school dance there are 132 boys,89 girls,and 14 adults

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3 years ago

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A circle centered at the origin has a radius of 10 units. The terminal side of an angle, Theta, intercepts the circle in Quadran

Tanzania [10]

Since the circle is centered at the origin, we can use the equations
x² + y² = r²
x = r cos θ
y = r sin θ

We know y = 8 and r = 10. Solving for x
x² + 8² = 10²
x = 6

From this equation:
x = r cos θ
6 = 10 cos θ
cos θ = 6/10 = 0.6

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3 years ago

A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

3 0

3 years ago

Write this number in scientific notation 0.000000358

Fittoniya [83]

Step-by-step explanation:

0.000000358 written as scientific notation is

$3.58 \times {10}^{ - 7}$

8 0

3 years ago

Ab^2-4/10 when a=4 b=6

hammer [34]

$\huge\text{Hey there!}$

$\large\boxed{\rm{\dfrac{ab^2 - 4}{10}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{4(6)}^2 -4}{10}}}$

$\large\boxed{\rm{6^2}}$

$\large\boxed{\rm{= 6 \times6}}$

$\large\boxed{\rm{= \bf 36}}$

$\large\boxed{\rm{\rightarrow\dfrac{4(\bold{36)}- 4}{10}}}}$

$\large\boxed{\rm{4(36)}}$

$\large\boxed{\rm{= \bf 144}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{144} - 4}{10}}}$

$\large\boxed{\rm{\bold{144} - 4}}$

$\large\boxed{= \rm{\bf 140}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{140}}{10}}}$

$\large\boxed{\rm{= \bf 14}}$

$\huge\boxed{\rm{Therefore, your\ answer\ is: \mathsf{14}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

4 0

2 years ago