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vitfil [10]
3 years ago
9

If ItsAkelia (me) had 1M subs and M00dybear had 1M who had more?

Mathematics
2 answers:
Archy [21]3 years ago
8 0

Answer:

If you both have 1M subs then its the same, not one person has more

galben [10]3 years ago
7 0

Answer:

Why try to impersonate Akeila?

Step-by-step explanation:

You spelled it wrong,  It's A K E I L A. I know this BECAUSE I'VE TALKED TO HER. If you wanna go and impersonate someone, go do Addison Rae-cist, cause nobody's dealing with this. Akeila is a sweet girl, and wouldn't ask selfish questions like this.

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ankoles [38]
C is the answer to this question
7 0
3 years ago
SOMEONE PLEASE HELP THANK YOUUU!!! I REALLY NEED IT
Tpy6a [65]

Answer: 3, 4

Step-by-step explanation:

and the common factor between these 2 numbers is 1 so 3,4 is its greatest factor

8 0
2 years ago
For the line that passes through Y(3,0), parallel to DJ with D(-3,1) and J(3,3), complete the following: Find the slope. Write a
Ulleksa [173]

I am going to graph the situation on an external graphing utility and show you the answer, it will take a

minute, stay with me.

m\text{ = }\frac{rise\text{ }}{\text{run}}=\frac{change\text{ in y}}{\text{change in x}}=\frac{3}{1}=3y\text{ = mx+b}\rightarrow\text{ b =-1}

So the equation of the line is.

y\text{ =3x -1}y\text{ -1 = m(3-0)}

8 0
1 year ago
Which expression is equivalent to<br> ^3 sqrt 1/1000 c^9 d^12
tamaranim1 [39]

Answer:

\sqrt[3]{ \frac{1}{1000} {c}^{9}  {d}^{12}  }  \\  =  \frac{1}{10}  {c}^{3}  {d}^{4}

5 0
3 years ago
A metalworker has a metal alloy that is 15​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou
coldgirl [10]

18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.

<u>Step-by-step explanation:</u>

Let x = kg of 15% copper alloy

Let y = kg of 60% copper alloy

Since we need to create 90 kg of alloy we know:

x + y = 90

51% of 90 kg = 45.9 kg of copper

So we're interested in creating 45.9 kg of copper

We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:

0.15x + 0.60y = 45.9

but

x + y = 90

x= 90 - y

substituting that value in for x

0.15(90 - y) + 0.60y = 45.9

13.5 - 0.15y + 0.60y = 45.9

0.45y = 32.4

y = 72

Substituting this y value to solve for x gives:

x + y = 90

x= 90-72

x=18

Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.

6 0
2 years ago
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