Answer: 0.01 m/s2
Explanation:
Given that:
Velocity of supertanker = 7.2 m/s (about 12 mph)
Time taken = 12 min
(Since the SI unit of time is seconds, convert 12 minutes to seconds
1 minute = 60 seconds
12 minutes = 12 x 60 = 720 seconds)
Average deceleration = ?
Recall that deceleration is obtained by dividing velocity by time taken.
i.e Deceleration = velocity / time
Deceleration = 7.2 m/s / 720 seconds
= 0.01 m/s2
Thus, the magnitude of its average deceleration is 0.01 meters per second squared.
Answer: 1.62 m
Explanation: In order to solve this problem we have to use the definition of Coulomb force whic is given by:
F=(k*q1*q2)/d^2 where k is a constant 9*10^9 N/C^2*m^2. d is the distance between tha charges q1 and q2.
then we can:
d^2= (k*q1*q2)/F= (9*10^9*30.3*10^-6*68.2*10^-6)/7.09=1.62 m
(note we have considered q2 as positive because we are determining d^2 by using the magnitude of the electric Force bewteen the charges).
Answer:
The ratio of the momentum imparted to gun #1 to that imparted to gun #2 is equal to 2 : 1
Explanation:
Detailed explanation and calculation is shown in the image below