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natulia [17]
3 years ago
9

4. What is the volume of a cube whose side is 10 cm?

Physics
2 answers:
Gemiola [76]3 years ago
8 0

Answer:

D.

Explanation:

Volume of the cube = (Length)³

V = (10 m)³

V = 10³ m³

tekilochka [14]3 years ago
4 0

Answer: Answer: The volume of the cube is 10^-3 m^3

:

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Which of the following has the least resistance?<br><br> wood<br> iron<br> copper<br> silver
Neporo4naja [7]

Answer:

Probably wood

Explanation:

6 0
3 years ago
4. Two forces act on a 2 kg object as shown. What is the magnitude of the acceleration of the object?
aleksandrvk [35]

The resultant force on the object is

∑ <em>F</em> = 〈0, 8〉 N + 〈6, 0〉 N = 〈6, 8〉 N

which has a magnitude of

<em>F</em> = √((6 N)² + (8 N)²) = √(100 N²) = 10 N

By Newton's second law, the acceleration has magnitude <em>a</em> such that

<em>F</em> = <em>m a</em>

10 N = (2 kg) <em>a</em>

<em>a</em> = (10 N) / (2 kg)

<em>a</em> = 5 m/s²

so the answer is B.

4 0
3 years ago
As a planet's semimajor axis gets smaller, its speed will _______ and its period will _________ .
Rufina [12.5K]
Well first of all, a planet doesn't have a semimajor axis, although it's orbit does.

In an orbit with a smaller semimajor axis, the planet moves faster, and its orbital period is shorter.

That's why the International Space Station circles the Earth in less time than the Moon does.
4 0
3 years ago
A 4.0-kg object is supported by an aluminum wire of length 2.0 m and diameter 2.0 mm. How much will the wire stretch?
forsale [732]

Answer:

The extension of the wire is 0.362 mm.

Explanation:

Given;

mass of the object, m = 4.0 kg

length of the aluminum wire, L = 2.0 m

diameter of the wire, d = 2.0 mm

radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

A = π(0.001)² = 3.142 x 10⁻⁶ m²

The downward force of the object on the wire is given by;

F = mg

F = 4 x 9.8 = 39.2 N

The Young's modulus of aluminum is given by;

Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm

Therefore, the extension of the wire is 0.362 mm.

8 0
3 years ago
Please help me out as soon as you can. Really need help.
olga nikolaevna [1]
The answer would be 6 because 2.0x3= 6

(newton’s 2nd law)

mark me brainliest
4 0
3 years ago
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