Answer:
Q = 160.36[kJ], is the heat lost.
Explanation:
This is a thermodynamic problem where we can find the latent heat of vaporization, at a constant temperature of 100 [°C].
We know that for steam at 100[C], the enthalpy is
![h_{gas} = 2675.6[kJ/kg]](https://tex.z-dn.net/?f=h_%7Bgas%7D%20%3D%202675.6%5BkJ%2Fkg%5D)
For liquid water at 100[C], the enthalpy is
![h_{water} = 419.17[kJ/kg]](https://tex.z-dn.net/?f=h_%7Bwater%7D%20%3D%20419.17%5BkJ%2Fkg%5D)
Therefore
![h_{g-w} = 2675.6-419.17 = 2256.43[\frac{kJ}{kg} ]](https://tex.z-dn.net/?f=h_%7Bg-w%7D%20%3D%202675.6-419.17%20%3D%202256.43%5B%5Cfrac%7BkJ%7D%7Bkg%7D%20%5D)
The amout of heat is given by:
![Q=h_{g-w}*m\\ where:\\m = mass = 0.07107[kg] = 71.01[g]\\Q = heat [kJ]\\Q =2256.43*0.07107\\Q=160.36[kJ]](https://tex.z-dn.net/?f=Q%3Dh_%7Bg-w%7D%2Am%5C%5C%20where%3A%5C%5Cm%20%3D%20mass%20%3D%200.07107%5Bkg%5D%20%3D%2071.01%5Bg%5D%5C%5CQ%20%3D%20heat%20%5BkJ%5D%5C%5CQ%20%3D2256.43%2A0.07107%5C%5CQ%3D160.36%5BkJ%5D)
Answer:
a = 6.53 m/s^2
v = 11.5689 m/s
Explanation:
Given data:
engine power is 217 hp
70 % power reached to wheel
total mass ( car + driver) is 1530 kg
from the data given
2/3 rd of weight is over the wheel
w = 2/3rd mg
maximum force

we know that F = ma


the new power is 


solving for speed v

![v = 0.7 \frac{217 [\frac{746 w}{1 hp}]}{1500 \times 6.53}](https://tex.z-dn.net/?f=v%20%3D%200.7%20%5Cfrac%7B217%20%5B%5Cfrac%7B746%20w%7D%7B1%20hp%7D%5D%7D%7B1500%20%5Ctimes%206.53%7D)
v = 11.5689 m/s
Answer:
The materials used to make electronic components like transistor and integrated, circuit behave as if effective particles known as electron through them, causing electrical properties
Answer:
34.70 N
Explanation:
Given :
F~ 1 = 43 N in direction 38◦
F~ 2 = 26 N in direction −140◦
F~ 3 = 27 N in direction 110◦
Therefore,
F~x = 43 cos (38) + 26 cos (-140) + 27 cos (110)
= 43 (0.7) + 26 (-0.7) + 27 (-0.3)
= 3.8
F~y = 43 sin (38) + 26 sin (-140) + 27 sin (110)
= 43 (0.6) + 26 (-0.6) + 27 (0.9)
= 34.5
so, F~ = 
= 34.70 N
The efficiency of steam engine is 26.66 %.
<h3>What is Efficiency?</h3>
The efficiency is defined as the work done by the engine divided by the heat supplied.
Work done is the difference between the heat supplied and heat rejected.
So, efficiency η = (Qs -Qr) / Qs
Given is the heat supplied Qs = 225 Joules and heat rejected Qr =285 . then the work done is
W = 225 -225 = - 60 Joules
Efficiency η = 60/225 x 100%
η = 26.66 %
Thus, the efficiency of the steam engine is 26.66 %.
Learn more about efficiency.
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