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3241004551 [841]
3 years ago
12

I Need Help With This One

Mathematics
1 answer:
Grace [21]3 years ago
7 0

Answer:

42.1

Step-by-step explanation:

First find the circumference

C = 2* pi * r

C = 2 * pi * 9.1

C = 18.2 pi

C =57.1769863  ( using the pi button)

Then the fraction of a circle the arc is

265/ 360 =53/72

Multiply this times the circumference

53/72 * 57.1769863 =42.08861491

To the nearest tenth

42.1

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A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sam
Scorpion4ik [409]

Answer:

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the real population proportion of students who take notes

\hat p represent the estimated proportion of students who take notes

n is the sample size required  

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

Confidence interval

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.64  

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

6 0
3 years ago
Helppppp and you get some sweet candyyyy
Katyanochek1 [597]

Answer:

your answer is c l hipe this helps u

4 0
3 years ago
Read 2 more answers
You are assigned 32 math exercises for homework. You complete 87.5 of these before dinner. How many do you have left to do after
VARVARA [1.3K]

Answer:

4

Step by step:

This is if the question is saying you completed 87.5% of the exercises. Otherwise, I don't know what it is asking.

87.5% of 32=28

32-28=4

6 0
2 years ago
Michael, whose eyes are five feet off the ground, is standing 26 feet away from the base of a building, and he looks up at a 65°
yawa3891 [41]

Answer:

Dear user,

Answer to your query is provided below

The building is 60.77 ft tall.

Step-by-step explanation:

Explanation is provided below in the image attached

3 0
3 years ago
In 1990, 1000 adults were randomly selected and each was asked if they smoked, 300
Oduvanchick [21]

Answer:

 The proportion of smokers was higher in 1990 than in 2000

Step-by-step explanation:

Solution

Recall that,

The total number of sample 1 (n1) = 1000

Total  sample 2 number  (n2) = 2000

The number of favourable events (X1) = 300

The number of favourable events (X2) = 500

so,

p₁ = X₁/n₁ = 300/1000 = 0.3

p₂ = X₂/n₂ =500/2000 =0.25

α = 0.05

We are interested in testing the hypothesis.

The  hypothesis (Null) ....>  H₀ : p₁ = p₂

Alternate hypothesis------ > H₁ : p₁ > p₂

Thus,

P = X₁ + X₂/ n₁ + n₂

P =300 + 500/1000 +2000

P =800/3000

=0.2667

Now,

Z₀ = P₁ - P₂/√ P (1 -P) (1/n₁ + 1/n₂)

Z₀ =  0.3 - 0.25/√0.2667  (1 - 0.2667) (1/1000 + 1/2000)

Z₀ = 0.4999999999999999/√ 0.2667 (0.7333000000000001) (0.001 +0.0005)

Then,

Z₀ = 0.4999999999999999/√0.00029335666500000004

Z₀ = 2.9193

so,

zα/2 = z0.05/2 =z0.025

zα/2 = 1.6448536269514722

Now, we apply the decision rule:

Decision Rule: Reject the null hypothesis if the statistic value test is higher than the critical value 1.6448536269514722

The statistic value, 2.9193 is greater than the critical value 1.6448536269514722,  then we will reject the null hypothesis.

Therefore, the proportion of smokers was higher in 1990 than in 2000

3 0
3 years ago
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