Answer:
<em>The area of the trapezium is 168</em>
Step-by-step explanation:
<u>Area of a Trapezoid</u>
Given a trapezoid of parallel bases b1 and b2, and height h, the area is calculated with the formula:

The trapezoid in the figure has b1=15 and b2=27. We need to find the height. If we focus on triangle BCD, we can calculate the height as the distance EC by using the Pythagora's Theorem:

The side BC can be found as half the difference of the bases:

Solving for EC:


Now we have the height, calculate the area:


A = 168
The area of the trapezium is 168
D I think because I did the math