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rewona [7]
3 years ago
14

What is the positive root of the equation x^2 + 5x = 150?

Mathematics
1 answer:
Montano1993 [528]3 years ago
7 0

Answer:

10

Step-by-step explanation:

x = 10, -15

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Helen kulman is a secretary she earned $10.65 per hour she worked 38 hours last week what is her straight time pay
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Complete the table for the number of trees planted compared to the number of trees that continue to
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3 years ago
One factor of 2x^2-32y^2 is
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6 0
3 years ago
The vertex of this parabola is at (-5,-2). when the x-value is -4, the y-value is 2. what is the coefficient of the squared expr
Westkost [7]
Vertex:  (-5,-2); parabola opens up; 

General form of the equation for a vertical parabola opening up is:

y-k = a(x-h)^2; knowing that the vertex is at (-5,-2), we can write:

y+2 = a(x+5)^2.  We need to find the value of the coefficient a.

From the graph we see that y is 10 when x is approx. -1 3/4 (or -7/4).

subst. these values into y+2 = a(x+5)^2, we get:

10 + 2 = a(-7/4 + 5)^2, or 12 = a(13/4)^2, or   1 = a(169/16).

Solving for a:  a = 16/169 = 0.09, or approx 16/160, or 1/10.  Unfortunately, this is not close to any of the four answer choices.

I thought it best to try again, and fortunately my second try was correct:

10+2 = a(13/4)^2, or  (169/16)a.  Thus, 12 = a(169/16)

                                   12
Solving for a:  a = ------------- = 1.14.  The answer choice closest to this is 1.
                                169/16

Answer A is correct.



6 0
4 years ago
Read 2 more answers
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