(100+3-4(4-5))/(6+5+5+5+300)
=(100+3-16+20)/(321)
=(107)/(321)
=1/3
Hope it helps : )
Answer:
1. (a-c)
+ b
2. 9m + 2
3. 6a
4. (5a - 3b)
Step-by-step explanation:
1. since a and c share the same squareroot x, you can combine these together.
2. First add like terms together. 4m - m + 6m = 9m. Then 5
and -3
combined equals 2
3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a
4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:
5a
- 3b
We can combine the two like terms and get the final answer above.
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Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation

Solve for S(t):


The left side is the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F800%7DS%28t%29%5Cright%5D%3D%5Cdfrac8%7B100%7De%5E%7Bt%2F800%7D)
Integrate both sides:



There's no sugar in the water at the start, so (a) S(0) = 0, which gives

and so (b) the amount of sugar in the tank at time t is

As
, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.
Answer:
9
Step-by-step explanation:
(9*3) = 27 which is 20 more than 7
Answer:
$18.75
Step-by-step explanation:
Let
y = Total cost
x = number of kilometers
The equation:
y = 3.75 + 1.50x
If x = 10 km
y = 3.75 + 1.50(10)
= 3.75 + 15
= 18.75
y = $18.75
y = Total cost = $18.75