That would be ten factorial, 10!, or 10*9*8*7*6*5*4*3*2*1, which would be 3628800




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Find Total :
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

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Find Average :
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



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
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The value of x
3x°+46°+(2x-1°)=180°(angle sum of △)
5x+45=180°
5x=180°-45
x=135÷5
x=27
x is 27
put x into angle B,we have
2(27)-1
=53
thus angleB is 53°
hope it helps c:
The values of the number is 43
x+21=64
subtract 21 on each side
x = 43
Answer:
(2,-5) and (2,1).
Step-by-step explanation:
We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.
A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.
Standard form of a circle is

where, (h,k) is center and r is the radius.


Now, put x=2.




Taking square root on both sides.




So, the y-coordinates of the points are -5 and 1.
Therefore, the required points are (2,-5) and (2,1).