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Alenkinab [10]
3 years ago
8

A rectangle has an area of 102 cm2. The length of the rectangle is 17 cm.

Mathematics
1 answer:
densk [106]3 years ago
6 0
102 / 17 = 6 
6 is the width of the rectangle 
17 x 2 + 6 x 2 = the perimeter
34 + 12 = 46  p=46 
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C) On Sunday, there were 28 students present in class five. 18 of them were boys and the rest were girls. If only 4 girls were a
sammy [17]

There are 14 girls in class five.

<h3>How many of the students are girls?</h3>

28 students were present in class five, such that 18 of them were boys.

The number of girls on Sunday is given by the difference:

28 - 18 = 10

And we know that 4 girls did not go to school on that day, so the total number of girls on class five is:

10 + 4 = 14

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6 0
2 years ago
a taxi cab in myrtle beach charges $2 per mile and $1 for every person. if a taxi cab ride for two people cost $12, how far did
Fiesta28 [93]

Answer:

5 miles

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Solve the following equation for 0° ≤ θ &lt; 360°. Use the "^" key on the keyboard to indicate an exponent. For example, sin2x w
Margarita [4]

Answer: 2sin^2x+sin2x+cos2x=0 ..... (1).

By using the trigonometric identities below :

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2sin^2x+2sinxcosx+cos^2x-sin^2x=0

By combining like terms .

sin^2x+2sinxcosx+cos^2x=0.....(2)

The equation (2) is equivalent to the following expression (3).

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sinx+cosx=0

cosx=-sinx

divide both sides by cosx

1=-sinx/cosx

-1=sinx/cosx

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substitute

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tangent is negative in 2nd and 4th quadrants

tan135º=-1 (one answer)

tan315º=-1 (second answer)

Step-by-step explanation:

Please refer to the trigonometric identities used and explained above .

5 0
3 years ago
Help me please thank you so much
wel

Answer: Susan, sam forgot to flip the signs while dividing a negative number.

6 0
3 years ago
Give all solutions if the nonlinear system of equations, including those with no real complex components.
konstantin123 [22]
\left\{\begin{array}{ccc}y=x^2+6x\\4x-y=-24\end{array}\right\\\\substitute:\\\\4x-(x^2+6x)=-24\\\\4x-x^2-6x+24=0\\\\-x^2-2x+24=0\\\\a=-1;\ b=-2;\ c=24\\\\\Delta=b^2-4ac

\Delta=(-2)^2-4\cdot(-1)\cdot24=4+96=100\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{100}=10\\\\x_1=\frac{2-10}{2\cdot(-1)}=\frac{-8}{-2}=4;\ x_2=\frac{2+10}{2\cdot(-1)}=\frac{12}{-2}=-6\\\\y_1=4^2+6\cdot4=16+24=40;\ y_2=(-6)^2+6\cdot(-6)=36-36=0\\\\Answer:\\x=4\ and\ y=40\ or\ x=-6\ and\ y=0
4 0
3 years ago
Read 2 more answers
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