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Flura [38]
2 years ago
13

1. What is the approximate area of a circle with a diameter of 20 inches?

Mathematics
1 answer:
ad-work [718]2 years ago
7 0

Answer:

1. 100\pi

2. 27 cm^{3}

3. 30

Step-by-step explanation:

Area = \pir^{2}

       = \pi x 10x^{2}

       = 100\pi

Volume = l x w x h

             = 3 x 3 x 3

             = 27

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1. Find the value of 8.3 x 24.2 x 0.03. Round your answer to the nearest hundredth.
MrMuchimi

The rounded value is option B) 6.03 which is rounded to the nearest hundredth.

<u>Step-by-step explanation:</u>

  • To find the value of 8.3 x 24.2 x 0.03, we need to multiply the given numbers to get a decimal value.
  • And then, after getting the value of 8.3 x 24.2 x 0.03 it should be rounded to the nearest hundredth.

<u>So, let's multiply the numbers first :</u>

8.3 × 24.2 × 0.03 = 6.0258

The value is 6.0258

<u>To round the value 6.0258 to the nearest hundredth :</u>

  • The first number next to the decimal point represents the tenth.
  • The second number next to the decimal point is the hundredth.
  • The third number next to the decimal point is thousandth.

Therefore, to round the value to the nearest hundredth, look for the thousandth number is either less than 5 or greater and or equal to 5.

If, thousandth place is greater or equal to 5, then the hundredth number should be increased by 1.

The hundredth is 6.02 and the number in the thousandth place is 5. So add 1 to the hundredth place.

The value is rounded to 6.03 to the nearest hundredth.

5 0
3 years ago
PLEASE BE QUICK!
Svetach [21]
The answer is 0.73 hope it helps
3 0
3 years ago
Am I right Help Me Please
lbvjy [14]
Yes you are correct good job
3 0
3 years ago
The maximum weight of a suitcase that an airline allows is 50 pounds. For every 1 pound, there is approximately 0.45 kilograms.
Marta_Voda [28]

Answer: 22.5 kg

Step-by-step explanation:

You did not attach a question, so I'm going to assume that it is asking for the maximum weight of a suitcase in kilograms.

3 0
2 years ago
What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

b must be equal to -6  for infinitely many solutions for system of equations y = 6x + b and -3 x+\frac{1}{2} y=-3

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

8 0
3 years ago
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