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otez555 [7]
3 years ago
10

A teacher asked the class to write an expression that Which of these expressions have an estimated

Mathematics
2 answers:
valkas [14]3 years ago
6 0

Answer:

9.7 x 2.84 and 6.25 x 4.76

Step-by-step explanation:

they are the only two that get close to 30 without getting over it

max2010maxim [7]3 years ago
3 0

Answer:

9.7 x 2.84 and 6.25 x 4.76

Step-by-step explanation:

they are the only two that get close to 30 without getting over it

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Answer is 3x(+7)= welcome
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3 years ago
Louie is trying to find a rectangular canvas for his art project. Its width must measure 20 inches and form a 35° angle with the
Anastasy [175]

Answer:

14.0 inches

Step-by-step explanation:

I took the quiz and got it right!

8 0
2 years ago
How do I solve log(2)t^3-1=-3?
Ne4ueva [31]
Assuming you mean
log_2(t^3-1)=-3
remember
log_a(b)=c translates to a^c=b
translate

log_2(t^3-1)=-3 translates to 2^{-3}=t^3-1
\frac{1}{2^3} =t^3-1
\frac{1}{8} =t^3-1
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3 0
3 years ago
Hannah was asked to make d the subject of the formula<br> d-7=4d+3/e<br> Finish her question.
tigry1 [53]

Answer:

d = \frac{-1}{e} - \frac{7}{3}

Step-by-step explanation:

In order to make d the subject of the formula, you need to isolate it.

- You started with d-7 = 4d + 3/e

- Move 4d to the left side by subtracting 4d from both sides to cancel it from the right so you have...

d - 7 = 4d + 3/e              This will leave you left with -3d - 7 = 3/e

-4d     -4d                          

- Then move over the -7 by adding 7 to both sides...

-3d - 7 = 3/e              This will leave you left with -3d = 3/e + 7

     +7          +7

- Finally to get d by itself divide both sides of the equation by -3 and you'll be left with...

d = \frac{3}{-3e} -\frac{7}{3}

- You can cancel out the 3 in the -3/3e and make it -1/e so your final answer will be

d = \frac{-1}{e} - \frac{7}{3}

5 0
3 years ago
An article in USA Today stated that Internal surveys paid for by directory assistance providers show that even the most accurate
MariettaO [177]

Answer:

a. 11.26 % b. 6.76 %. It appears so since 6.76 % ≠ 15 %

Step-by-step explanation:

a. This is a binomial probability.

Let q = probability of giving out wrong number = 15 % = 0.15

p = probability of not giving out wrong number = 1 - q = 1 - 0.15 = 0.75

For a binomial probability, P(x) = ⁿCₓqˣpⁿ⁻ˣ. With n = 10 and x = 1, the probability of getting a number wrong P(x = 1) = ¹⁰C₁q¹p¹⁰⁻¹

= 10(0.15)(0.75)⁹

= 1.5(0.0751)

= 0.1126

= 11.26 %

b. At most one wrong is P(x ≤ 1) = P(0) + P(1)

= ¹⁰C₀q⁰p¹⁰⁻⁰ + ¹⁰C₁q¹p¹⁰⁻¹

= 1 × 1 × (0.75)¹⁰ + 10(0.15)(0.75)⁹

= 0.0563 + 0.01126

= 0.06756

= 6.756 %

≅ 6.76 %

Since the probability of at most one wrong number i got P(x ≤ 1) = 6.76 % ≠ 15 % the original probability of at most one are not equal, it thus appears that the original probability of 15 % is wrong.

3 0
3 years ago
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