Answer:
Step-by-step explanation:
I just finished this exam review and it should be f(x)=4(^3sqrt16)^2x
Hope this helps you out!
Answer:
less than 1 1/2 gallons
Step-by-step explanation:
1/3 + 1/6 = 1/2, so the sum of the three cans is more than 1 by the difference between 1/5 and 1/6. That difference is 1/30 gallon. The sum is 1 1/30 gallons, which is less than 1 1/2 gallons.
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A suitable common denominator is 2·3·5 = 30. Then the sum of the fractions is ...
1/3 + 1/5 + 1/2
= 10/30 + 6/30 + 15/30
= 31/30 = 1 1/30 . . . . . less than 1 1/2
In decimal, 1/3 ≈ 0.333, 1/5 = 0.200, 1/2 = 0.500, so the sum is ...
0.333 +0.200 +0.500 = 1.033
which is less than 1.5.
Step-by-step explanation:
Area of circular pond=22/7×14×14
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>2</em><em>2</em><em>/</em><em>7</em><em>×</em><em>1</em><em>9</em><em>6</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>6</em><em>1</em><em>6</em><em>m</em>
Answer:
A) Particular solution:
B) Homogeneous solution:
C) The most general solution is
Step-by-step explanation:
Given non homogeneous ODE is
To find homogeneous solution:
To find particular solution:
Substituting 
in (1)
Equating the coefficients
The general solution is
from (2) ad (3)
Answer:
am i suppoesd to do number 7 as well?
Step-by-step explanation:
Two wires
tether a balloon to the ground, as shown. How
high is the balloon above the ground? (Must Use Right
Triangle Trigonometry)
look at picture
