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3 years ago

The distance between P and T on the coordinate grid is units. (Input whole numbers only.)

Mathematics

2 answers:

nlexa [21]3 years ago

7 0

Answer:ummm do you have a picture of the question?

Step-by-step explanation:

bonufazy [111]3 years ago

3 0

Answer:

PaT UwU

Step-by-step explanation:

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Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago

Simplify the expression

Studentka2010 [4]

The answer to your question is
x^33

7 0

3 years ago

Harper knows he is 50 yards from school. The map on his phone shows that the school is 34 inch from his current location. If Har

AlexFokin [52]

Answer:

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. We know that 1 yard is 36 inches, therefore, 50 yards expressed in inches is:

2. If he is 50 yards from school and the map shows that the school is 34 inches from his current location, when it shows 3 inches the real distance is:

<u> (1800)(3in)/24in=158.82</u>

3. If you can to express it in yards:

<h2><u>Therefore, the answer is: 158.82 inches or 4.41 yards.</u></h2>

4 0

3 years ago

Please answer. What is section B?<br> Thank you

Semenov [28]

Answer:

erm

Step-by-step explanation:

(8,8000)

5 0

3 years ago

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there is a string green and white strung around a mirror. For every 6 green lignts there are 4 white. If there are 30 green ligh

Klio2033 [76]

6 times 5 is 30 so 4 times 5 eaquls 20
The answer is 20

7 0

3 years ago

The distance between P and T on the coordinate grid is units. (Input whole numbers only.)​

The distance between P and T on the coordinate grid is units. (Input whole numbers only.)