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3 years ago

According to the Arrhenius theory, when a base dissolves in water it produces

1 answer:

5 0

Answer: produces hydronium ions (H 3O +) as follows: Chemists often simply call this the hydrogen ion, and use the notation H + (aq) as shorthand for the H 3O + (aq) ion.

Explanation:

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Nitrogen monoxide, NO, reacts with hydrogen, H₂, according to the following equation.

Anvisha [2.4K]

Answer : The rate law for the overall reaction is, $Rate=k[NO]^2[H_2]$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

As we are given the mechanism for the reaction :

Step 1 : $2NO+H_2\rightarrow N_2+H_2O_2$ (slow)

Step 2 : $H_2O_2+H_2\rightarrow 2H_2O$ (fast)

Overall reaction : $2NO+2H_2\rightarrow N_2+2H_2O$

The rate law expression for overall reaction should be in terms of $NO\text{ and }H_2$ .

As we know that the slow step is the rate determining step. So,

The slow step reaction is,

$2NO+H_2\rightarrow N_2+H_2O_2$

The expression of rate law for this reaction will be,

$Rate=k[NO]^2[H_2]$

Hence, the rate law for the overall reaction is, $Rate=k[NO]^2[H_2]$

8 0

4 years ago

The ideal of stationary orbit was first given by?

marusya05 [52]

Answer:

Neil Bohr

Explanation:

Thank me latur✊

8 0

3 years ago

for the following reaction, draw the major organic product and select the correct iupac name for the organic reactant. if there

denpristay [2]

For number two, the equation is balanced. Na in the reactant side has one atom and also in the product side. O has only one atom in the product and in the reactant. There are 2H’s in the reactant and in the product side (present in H2O, the 2 in H stands for 2 atoms of H). One atom of Cl is present in the reactant and product side.

For number three, the reactants are NaOH-sodium hydroxide and HCl-hydrogen chloride(hydrochloric acid). The products are NaCl-sodium chloride and H2O-water.

5 0

4 years ago

What would be the change in pressure in a sealed 10.0 l vessel due to the formation of n2 gas when the ammonium nitrite in 2.40

larisa86 [58]

The change in pressure in a sealed 10.0L vessel is 5.28 atm

calculation

The pressure is calculated using the ideal gas equation

That is P=n RT

where;

P (pressure)= ?

v( volume) = 10.0 L

n( number of moles) which is calculated as below

write the equation for decomposition of NH₄NO₂

NH₄NO₂ → N₂ +2H₂O

Find the moles of NH₄NO₂

moles = molarity x volume in liters

= 2.40 l x 0.900 M =2.16 moles

Use the mole ratio to determine the moles of N₂

that is from equation above NH₄NO₂:N₂ is 1:1 therefore the moles of N₂ is also =2.16 moles

R(gas constant) =0.0821 l.atm/mol.K

T(temperature) = 25° c into kelvin = 25 +273 =298 K

make p the subject of the formula by diving both side by V

P = nRT/V

p ={ (2.16 moles x 0.0821 L.atm/mol.K x 298 K) /10.0 L} = 5.28 atm.

3 0

3 years ago

Read 2 more answers

One mole of an ideal gas is expanded from a volume of 1.00 liter to a volume of 8.00 liters against a constant external pressure

Leya [2.2K]

Answer : The work done on the surroundings is, 709.1 Joules.

Explanation :

The formula used for isothermally irreversible expansion is :

$w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)$

where,

w = work done

$p_{ext}$ = external pressure = 1.00 atm

$V_1$ = initial volume of gas = 1.00 L

$V_2$ = final volume of gas = 8.00 L

Now put all the given values in the above formula, we get :

$w=-p_{ext}(V_2-V_1)$

$w=-(1.00atm)\times (8.00-1.00)L$

$w=-7L.atm=-7\times 101.3J=-709.1J$

The work done by the system on the surroundings are, 709.1 Joules. In this, the negative sign indicates the work is done by the system on the surroundings.

Therefore, the work done on the surroundings is, 709.1 Joules.

4 0

3 years ago