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Zarrin [17]
3 years ago
12

What is the answer??????​

Chemistry
2 answers:
Citrus2011 [14]3 years ago
7 0

Answer:

True

Explanation:

True

Grace [21]3 years ago
5 0

the large intestine absorbs fluids so it's false

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How do you determine how many electron energy levels an element has
vivado [14]

Answer:36

Explanation:

Atoms must have equal numbers of protons and electrons. In our example, an atom of krypton must contain 36 electrons since it contains 36 protons. Electrons are arranged around atoms in a special way.

4 0
4 years ago
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Three clues that indicate chemical change <br>​
Bad White [126]

Explanation:

temperature

taste

and acidity rate

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3 years ago
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How many moles are present in 5.67x1025 atoms of Carbon (C)?
Ulleksa [173]

Answer:

94 moles of Carbon

Explanation:

From the question,

Using Avogadro's constant

1  mole of every element contains 6.03×10²³ atoms of the element

If 1 mole of Carbon contains 6.03×10²³ atoms of Carbon,

Then, x mole of Carbon will contain 5.67×10²⁵ atoms of Carbon

1 mole of C ⇒ 6.03×10²³ atoms of C

x mole of C ⇒ 5.67×10²⁵ atoms of C

solve for x

x = (1× 5.67×10²⁵)/6.03×10²³

x = 94.03 moles of Carbon

x ≈ 94 moles of Carbon

6 0
3 years ago
In the formation of silicon carbide represented by the chemical equation sio2+3c--&gt;sic+2co 8.0 moles of each reactant are ava
Mashcka [7]

Answer:

7.3

Explanation:

3 0
3 years ago
The drug propanolol, which is used as an anxiolytic (relieves anxiety) has a half-life of 3.9 h. How long does it take for 80% o
Olenka [21]

Answer:

After 9.0 hours

Explanation:

Using the decay equation, we can write the amount of drug propanol after time t as:

m(t)=m_0 e^{-\lambda t} (1)

where

m(t) is the mass left at time t

m_0 is the initial mass of the substance

\lambda is the decay constant

t is the time

The decay constant is related to the half-life of the substance as follows:

\lambda=\frac{ln2}{t_{1/2}}

where t_{1/2} is the half-life.

Here we have

t_{1/2}=3.9 h

So the decay constant is

\lambda=\frac{ln 2}{3.9}=0.178 h^{-1}

We want to find the time t after which the dose is 80% of the initial dose is eliminated, so the time t after which 20% of drug is left, so

\frac{m(t)}{m_0}=0.20

Substituting eq(1) and solving for t, we find:

t=-\frac{ln(\frac{m(t)}{m_0})}{\lambda}=-\frac{ln(0.20)}{0.178}=9.0 h

3 0
3 years ago
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