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Nady [450]
3 years ago
7

When scientists use one of their five senses to gather information, they are A. making an observation. B. making an inference. C

. predicting a relationship D. drawing a conclusion.
Chemistry
2 answers:
Goshia [24]3 years ago
7 0

A. making an observation.

Explanation:

When scientists use one of their five sense to gather information, they are simply making an observation.

Most physical properties of matter are studied using sense of taste, of feel, sight, hearing and smell.

  • Observation is the act of making a measurement or studying.
  • It helps to investigate particular phenomenon in nature.
  • Most observations made with our senses are usually qualitative in nature.
  • They cannot be assigned values like quantitative ones.

learn more:

Observations brainly.com/question/5096428

#learnwithBrainly

Stels [109]3 years ago
6 0

A. Making and observation

Explanation:

When scientists use one of their five senses to gather information, they are making an observation.

Much of scientific knowledge has been gained through observation. By using the senses of sight, smell, touch, taste, and hearing, there are many things about the world that can be learned.

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An overseas flight leaves New York in the late afternoon and arrives in London 8.50 hours later. The airline distance from New Y
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Answer:

v = 658.82 km/h

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The distance between New York and London is 5.6\times 10^3\ km

Time taken from New York to London is 8.5 hours

We need to find the average speed of the plane.

Total distance covered divided by the total time taken is equal to the average speed of an object. So,

v=\dfrac{d}{t}\\\\v=\dfrac{5.6\times 10^3\ km}{8.5\ h}\\\\v=658.82\ km/h

So, the average speed of the plane is 658.82 km/h.

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The measurement 3.8 x 10^3 g could also be written as
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Read 2 more answers
What must be the molarity of an aqueous solution of trimethylamine, (ch3)3n, if it has a ph = 11.20? (ch3)3n+h2o⇌(ch3)3nh++oh−kb
Stolb23 [73]

0.040 mol / dm³. (2 sig. fig.)

<h3>Explanation</h3>

(\text{CH}_3)_3\text{N} in this question acts as a weak base. As seen in the equation in the question, (\text{CH}_3)_3\text{N} produces \text{OH}^{-} rather than \text{H}^{+} when it dissolves in water. The concentration of \text{OH}^{-} will likely be more useful than that of \text{H}^{+} for the calculations here.

Finding the value of [\text{OH}^{-}] from pH:

Assume that \text{pK}_w = 14,

\begin{array}{ll}\text{pOH} = \text{pK}_w - \text{pH} \\ \phantom{\text{pOH}} = 14 - 11.20 &\text{True only under room temperature where }\text{pK}_w = 14 \\\phantom{\text{pOH}}= 2.80\end{array}.

[\text{OH}^{-}] =10^{-\text{pOH}} =10^{-2.80} = 1.59\;\text{mol}\cdot\text{dm}^{-3}.

Solve for [(\text{CH}_3)_3\text{N}]_\text{initial}:

\dfrac{[\text{OH}^{-}]_\text{equilibrium}\cdot[(\text{CH}_3)_3\text{NH}^{+}]_\text{equilibrium}}{[(\text{CH}_3)_3\text{N}]_\text{equilibrium}} = \text{K}_b = 1.58\times 10^{-3}

Note that water isn't part of this expression.

The value of Kb is quite small. The change in (\text{CH}_3)_3\text{N} is nearly negligible once it dissolves. In other words,

[(\text{CH}_3)_3\text{N}]_\text{initial} = [(\text{CH}_3)_3\text{N}]_\text{final}.

Also, for each mole of \text{OH}^{-} produced, one mole of (\text{CH}_3)_3\text{NH}^{+} was also produced. The solution started with a small amount of either species. As a result,

[(\text{CH}_3)_3\text{NH}^{+}] = [\text{OH}^{-}] = 10^{-2.80} = 1.58\times 10^{-3}\;\text{mol}\cdot\text{dm}^{-3}.

\dfrac{[\text{OH}^{-}]_\text{equilibrium}\cdot[(\text{CH}_3)_3\text{NH}^{+}]_\text{equilibrium}}{[(\text{CH}_3)_3\text{N}]_\textbf{initial}} = \text{K}_b = 1.58\times 10^{-3},

[(\text{CH}_3)_3\text{N}]_\textbf{initial} =\dfrac{[\text{OH}^{-}]_\text{equilibrium}\cdot[(\text{CH}_3)_3\text{NH}^{+}]_\text{equilibrium}}{\text{K}_b},

[(\text{CH}_3)_3\text{N}]_\text{initial} =\dfrac{(1.58\times10^{-3})^{2}}{6.3\times10^{-5}} = 0.040\;\text{mol}\cdot\text{dm}^{-3}.

8 0
3 years ago
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