Question

After 2 hours, there are 1,400 mL of fluids remaining in a patient’s IV. The fluids drip at a rate of 300 mL per hour. Let x be the time passed, in hours, and y be the amount of fluid left in the IV, in mL. Write a linear function that models this scenario.

Answer 1

Answer:

$y(2) = 1400$

Using this condition we got:

$1400= -300*2 +b$

And solving for b we got:

$b= 1400+ 600= 2000$

So then our linear function is given by:

$y = -300x +2000$

Where y is the amount of fluid left and x the number of hours ellapsing

Step-by-step explanation:

We want to set up a linear function like this one:

$y = mx+b$

Where y is the amount of fluid left, m the slope and b the initial amount. From the info given we know thatm = -300. And we also have the following condition:

$y(2) = 1400$

Using this condition we got:

$1400= -300*2 +b$

And solving for b we got:

$b= 1400+ 600= 2000$

So then our linear function is given by:

$y = -300x +2000$

Where y is the amount of fluid left and x the number of hours ellapsing