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Alex17521 [72]
2 years ago
14

After 2 hours, there are 1,400 mL of fluids remaining in a patient’s IV. The fluids drip at a rate of 300 mL per hour. Let x be

the time passed, in hours, and y be the amount of fluid left in the IV, in mL. Write a linear function that models this scenario.
Mathematics
1 answer:
CaHeK987 [17]2 years ago
6 0

Answer:

y(2) = 1400

Using this condition we got:

1400= -300*2 +b

And solving for b we got:

b= 1400+ 600= 2000

So then our linear function is given by:

y = -300x +2000

Where y is the amount of fluid left and x the number of hours ellapsing

Step-by-step explanation:

We want to set up a linear function like this one:

y = mx+b

Where y is the amount of fluid left, m the slope and b the initial amount. From the info given we know thatm = -300. And we also have the following condition:

y(2) = 1400

Using this condition we got:

1400= -300*2 +b

And solving for b we got:

b= 1400+ 600= 2000

So then our linear function is given by:

y = -300x +2000

Where y is the amount of fluid left and x the number of hours ellapsing

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Write the word sentence as an inequality. <br> One plus a number y is no more than −13.
Serjik [45]
1+y \leq 13
6 0
3 years ago
HeLp!!
erica [24]

Answer:

C

Step-by-step explanation:

A constant correlation is essentially when the points on a scatter plot do not show any type of pattern or correlation; the points are literally scattered rather randomly, which would cause the graph to neither increase nor decrease.

Meanwhile, a positive correlation means that the points on the plot follow a line with a positive slope. In other words, it increases to the right.

Thus, the answer is C.

Hope this helps!

4 0
3 years ago
Read 2 more answers
Two cars start out together from the same place. they travel in opposite​ directions, with one of them traveling 5 miles per hou
Mashutka [201]
<u>Annotation</u>
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.


One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5  (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as  (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
\boxed{\boxed{ v_{1}=68mph} }
\boxed{\boxed{ v_{2}=63mph} }
7 0
3 years ago
Someone help me with this!
JulijaS [17]

Answer:

63

Step-by-step explanation:

you have to add

8 0
3 years ago
Read 2 more answers
Why is the HCF x*2 ? Please explain thanks for number d
erma4kov [3.2K]

Answer:

x² is HCF (Height common factor)

Step-by-step explanation:

Given:

x² , x³

Find:

HCF (Height common factor)

Computation:

HCF (Height common factor) is uused to find Height common factor from the given numbers.

x² , x³

Takling x² as common

x² (1 , x)

So,

x² is HCF (Height common factor)

7 0
3 years ago
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