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2 years ago

9

A spinner has red, green, blue and orange sections. The probability of landing on red is 2/3,on green 1/12, on blue is 1/12. Wha

t is the probability of landing on orange.

1 answer:

lesya [120]2 years ago

7 0

Answer: P(landing on orange)=1 - [2/3 + 1/12 + 1/12]

so <em><u>=1/6</u></em>

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Liam is setting up folding chairs for a meeting. If he arranges the chairs in 9 rows of the same length, he has 3 chairs left ov

exis [7]

9x + 3 = 7x +19

2x + 3 = 19

2x = 16

x = 8

So, x (8) is the number of chairs in each row with these setups.

Plug 8 into one of the equations and you will find how many chairs total there are.

9(8) + 3 = 75

There are 75 chairs total

8 0

3 years ago

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$

$\sigma = \sqrt{4996.78}$

$\sigma = 70.69$ --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

$c =0.95$

So:

$\alpha = 1 -c$

$\alpha = 1 -0.95$

$\alpha = 0.05$

Calculate the degree of freedom (df)

$df = n -1$

$df = 20 -1$

$df = 19$

Determine the critical value at row $df = 19$ and columns $\frac{\alpha}{2}$ and $1 -\frac{\alpha}{2}$

So, we have:

$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

$X^2_{0.975} = 8.907$ --- at $1 -\frac{\alpha}{2}$

So, the confidence interval of the standard deviation is:

$\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }$ to $\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }$

$70.69 * \sqrt{\frac{20 - 1}{32.852}$ to $70.69 * \sqrt{\frac{20 - 1}{8.907}$

$70.69 * \sqrt{\frac{19}{32.852}$ to $70.69 * \sqrt{\frac{19}{8.907}$

$53.76$ to $103.25$

8 0

2 years ago

A, b, c, and d please

DIA [1.3K]

<h2>Answers / Step-by-step explanation:</h2><h3>a. What is the length of one side of the square.</h3>

<em>Looking at the image, the radius (r) of the circle appears to cover half of the length of a side of the square. Hence, the side of the square has a length of </em><em>2r</em><em>.</em>

<em />

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em />

<h3>b. The formula A= πr² is used to find the area of a circle. The formula A=4r² can be used to find the area of the square. Write the ratio of the area of the circle to the area of the square in the simplest form.</h3>

<em /> $Ratio=\frac{\pi r^{2} }{4r^2} =\frac{\pi}{4}$ .

<em>Notice that the value "r²" disappears from the expression because is being multiplied and divided by it at the same time.</em>

<em />

$Ratio=\frac{4\pi }{16} =0.7854.$

<em />

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em />

c. Complete the table.

<em>To complete each cell of the table, simply take the equation of the asked parameter and substitute the value of r by the number indicated in the title of the column. For example, column 3 should be filled out like this:</em>

Area of Circle (units²): π(3)²or 9π.

Length of 1 Side of the Square: 2r= 2(3)= 6.

Area of Square (units²)= 4r²= 4(3)²= 36.

Ratio: $\frac{\pi}{4}$ .

<em>Do the same for all the other columns. </em>

<em>The answers to the table are presented on the attached image</em><em>.</em>

<em />

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em />

d. What can you conclude about the relationship between the area of the circle and the square?

<em>They will always have the same value, π/4, regardless of the size of the square and circle. As long as the circle borders meet the square's at the middle of each side of the square, the relationship will be the same</em><em>.</em>

4 0

2 years ago

Help pleaseeeeeeeeeeeee

malfutka [58]

Answer:

i) +3

2.) 15

3.)5/8

4.)+98

5.)27

6.)17

7.) 12/17

8.)12/17

9.)+5

10.) 3.2

7 0

3 years ago

What is the answer!?!?!?

77julia77 [94]

The price for hardcover books is 1.50 and the price for paperback is .50

8 0

3 years ago