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3 years ago

9

A spinner has red, green, blue and orange sections. The probability of landing on red is 2/3,on green 1/12, on blue is 1/12. Wha

t is the probability of landing on orange.

1 answer:

lesya [120]3 years ago

7 0

Answer: P(landing on orange)=1 - [2/3 + 1/12 + 1/12]

so <em><u>=1/6</u></em>

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3 years ago

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Answer:

Option (b) is correct.

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$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}$

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Simplify, we have,

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$(2^\frac{1}{4} )^4=2^{1}=2$

Thus, $(2^\frac{1}{4} )^4=2$

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