Let's solve for x.
−b3+3b2+8−x−5b2−9=5b3+852+17
Step 1: Add b^3 to both sides.
−b3−2b2−x−1+b3=5b3+869+b3
−2b2−x−1=6b3+869
Step 2: Add 2b^2 to both sides.
−2b2−x−1+2b2=6b3+869+2b2
−x−1=6b3+2b2+869
Step 3: Add 1 to both sides.
−x−1+1=6b3+2b2+869+1
−x=6b3+2b2+870
Step 4: Divide both sides by -1.
−x
−1
=
6b3+2b2+870
−1
x=−6b3−2b2−870
Answer:
x=−6b3−2b2−870
writing each one in prime factors:_
1
2
3
2 * 2
5
2 * 3
7
2* 2 * 2
3 * 3
2 * 5
so the smallest number ( the L.C.M) = 1*2*2*2*3*3*5*7 = 2520
The answer is 2520.
Answer:
C
Step-by-step explanation:
183-160=23 or 160+23=183
Hope this helps!
Answer:
There are 16 no-bake cookies.
Step-by-step explanation:
1 : 1 : 3
x : x : 48
x = 48 / 3
x = 16
Answer:
to solve use the distributive property and multiply
Step-by-step explanation:
I'm sorry I do not have the product
