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crimeas [40]
3 years ago
7

What's an expression that can be used to multiply 6 x 198 mentally

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
6 0
So first you do 6×2 since 198 is 2 less than 200

And if you do the math, it would be 12

After that, you do 6×200, since if you round off 198, it would be 209

And if you do the math again, it would be 1200


After that if you subtract 12 from 1200, you would get 1188

So the answer is 1188


( Even if you calculate 6×198the way it is, you would get 1188)


Hope this helps:)
disa [49]3 years ago
3 0
Sense it is metal math you do 6 x 200
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If your in school your teacher taught it: where’s your notes ? haha jk the right answer is B.) bc it’s going over 2 up 3.
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4 years ago
Please help meeeeeee
larisa [96]

Answer:

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4 0
4 years ago
Solve this equation: K - 8 =15
kupik [55]

Answer:

k=23

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    k-8-(15)=0  

Step by step solution :

STEP

1

:

Solving a Single Variable Equation

1.1      Solve  :    k-23 = 0  

Add  23  to both sides of the equation :  

                     k = 23

One solution was found :

k = 23

4 0
4 years ago
Read 2 more answers
Short Answer (6 Points) Solve for k.<br> N= p-k/j
suter [353]

Answer:

k = (p - N)j = pj - Nj

Step-by-step explanation:

N = p - k/j

k/j = p - N

(k/j)j = (p - N)j

k = (p - N)j = pj - Nj

8 0
4 years ago
Listed below are the ACT scores of 40 randomly selected students at a major university. (Use technology if you wish, Excel) 18 1
tiny-mole [99]

Answer:

A) See the picture

B) 14

C) 45%

Step-by-step explanation:

A) To create a histogram like the one on the picture you can use an online tool like socscistatistics where the number of classes is customizable

B) Because the question B and C have to be responded using a frequency table with 8 classes the answer is 14; the method of using cumulative frequency tables should only be considered as a way of estimation, that is because you obtain values that depend on your choice of class intervals. The way to get a better answer would be to use all the scores in the distribution

Pc1 = 100*(4/40) = 10

Pc2 = 100*(4/40) = 10

Pc3 = 100*(3/40) = 7.5

Pc4 = 100*(11/40) = 27.5

Pc5 = 100*(5/40) = 12.5

Pc6 = 100*(4/40) = 10

Pc7 = 100*(7/40) = 17.5

Pc8 = 100*(2/40) = 5

Pc8 + Pc7 + Pc6 + Pc5 + Pc4 + Pc3 + Pc2 = 90%

Therefore, From class 8 to class 2 is the top 90% of the applicants and the minimum score is 14.

C) Scores equal to or greater than 20 are from class 8 to class 5

Pc8 + Pc7 + Pc6 + Pc5 = 45%

5 0
3 years ago
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