A.
Divide the numbers
1 + 4x 2/2 • x =5x
1 + 4x + 1x =5x
Multiply by 1
1 + 4x + 1x=5x
Combine like terms
1 + 4x + x =5x
1 + 5x =5x
Subtract 1 from both sides of the equation
5x + 1 = 5x
5x + 1 - 1 =5x -1
Simplify
Subtract the numbers
5x = 5x -1
Subtract 5x from both sides of the equation
5x = 5x -1
5x - 5x = 5x -1 -5x
Simplify
0= -1
Result
0= -1
idk the ans in letter B
Of your numbers listed, 29 and 41 are the lengths of the hypotenuse of a Pythagorean triple.
Those triples are
(20, 21, 29)
(9, 40, 41)
_____
The On-Line Encyclopedia of Integer Sequences (OEIS) lists the hypotenuses of primitive triples as sequence number A020882.
Answer:
d=6.4m
Step-by-step explanation:
d=2r=2·3.2=6.4m
Answer:
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Step-by-step explanation:
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Answer:
10 x squared minus 4 y + 2 x squared minus y
Step-by-step explanation:
9x^2-2y+3x^2-3y
Collect like terms
9x^2+3x^2-2y-3y
=12x^2-5y
10 x squared minus 4 y + 2 x squared minus y
10x^2-4y+2x^2-y
Collect like terms
10x^2+2x^2-4y-y
=12x^2-5y
9x^2-2y+3x^2-3y is equivalent to
10x^2-4y+2x^2-y
Check all the options
6 x squared minus y + 6 x squared minus 5 y
6x^2-y+6x2-5y
12x^2-6y
6 x squared minus y + 3 x squared minus 4 y
6x^2-y+3x^2-4y
9x^2-5y
10 x squared minus 4 y + 2 x squared minus y
10x^2-4y+2x^2-y
12x^2-5y
11 x squared + 2 y + x squared minus 3 y
11x^2+2y+x^2-3y
12x^2-y
