r = sqrt(A/pi) r = sqrt(50/pi) r = sqrt(50)/sqrt(pi) r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi)) r = sqrt(50pi)/pi r = sqrt(25*2pi)/pi r = sqrt(25)*sqrt(2pi)/pi r = 5*sqrt(2pi)/pi
Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"
r = sqrt(A/pi) r = sqrt(27/pi) r = sqrt(27)/sqrt(pi) r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi)) r = sqrt(27pi)/pi r = sqrt(9*3pi)/pi r = sqrt(9)*sqrt(3pi)/pi r = 3*sqrt(3pi)/pi
Note: the same issue comes up as before in part a)
Comment The radius can be found by taking the square root of A divided by pi under the root sign.
Formula r = sqrt(A / pi) r = sqrt(A * pi/( pi * p)i) the root of pi^2 is pi r = sqrt(A * pi)/pi
Problem A r = √(50 * π) / π <<<< answer
Comment For each problem, all you need do is put in the given areas in A B C. I don't know what your input will do with the square root sign; you can write sqrt(50 * pi) / pi
