Start from the parent function 
In the first case, you are computing
In the second case, you are computing
![f(x+1)-2 /tex] There are two translation going on: when you transform [tex] f(x) \to f(x+k)](https://tex.z-dn.net/?f=%20f%28x%2B1%29-2%20%2Ftex%5D%3C%2Fp%3E%20%3Cp%3EThere%20are%20two%20translation%20going%20on%3A%20when%20you%20transform%20%5Btex%5D%20f%28x%29%20%5Cto%20f%28x%2Bk%29%20)
, you translate the function horizontally, 
units left if 
and units right if 
.
On the other hand, when you transform 
, you translate the function vertically, units up if and units down if .
So, the first function is the "original" parabola , translated 
units right and 
units up. Likewise, the second function is the "original" parabola , translated 
units left and 
units down.
So, the transformation from 
to 
is: go 
units to the left and units down
Answer:
Hope this helps :)
Step-by-step explanation:
15
(3^5)÷(3^5)
Simplify 3^5
243÷243
1
(3^5)÷(3^5)
3^5/3^5=3^5-5
3^5-5
3^5-5= 1
1
Formula: x^a/x^b=x^a-b
16
2^10/2^10
Cancel out 2^10
1
2^10/2^10
2^10/2^10=2^10-10
2^10-10
2^10-10=1
1
Formula: x^a/x^b=x^a-b
17
x^7/x^7x≠0
x≠0
18
(4x+2y)5÷(4x+2y)^5(4x+2y) ≠ 0
5/(4x+2y)^3 ≠ 0
5 ≠ 0
≠ =-y/2
19
No solution
20
p^4/p^4p ≠ 0
p≠ 0
no solution
The last one is the answer
Throwing a ball, shooting a cannon, diving from a platform and hitting a golf ball are all examples of situations that can be modeled by quadratic functions. ... In many of these situations you will want to know the highest or lowest point of the parabola, which is known as the vertex.
-2x^2=-15-5
-2x^2=-10
x^2=-5
X≠R i am not quite sure but...hope it helps :)
