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dangina [55]
3 years ago
7

How many moles of NH3 can you make from 0.37 moles of H2

Chemistry
2 answers:
NeTakaya3 years ago
7 0

Answer:

n_{NH_3}=0.25molNH_3

Explanation:

Hello,

In this case, the undergoing chemical reaction should be:

3H_2+N_2\rightarrow 2NH_3

Thus, since 0.37 moles of hydrogen are reacting, by using its 3:2 molar ratio with ammonia (NH3), we can compute the produced moles of NH3 as shown below:

n_{NH_3}=0.37molH_2 *\frac{2molNH_3}{3molH_2} \\\\n_{NH_3}=0.25molNH_3

Best regards.

uranmaximum [27]3 years ago
6 0

Answer:

The correct answer is 0.25 moles NH₃

Explanation:

First, we need to know the chemical equation for NH₃ formation from H₂. The balanced chemical reaction involved in NH₃ obtention is the following:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

According to this, 2 moles of NH₃ are formed from 3 moles of H₂. We can write that estequiometrical relation as: 2 moles NH₃/ 3 moles H₂.

From the problem, we have to calculate how many moles of NH₃ are produced from 0.37 moles H₂. So, we can simply multiply the number of moles of H₂ to obtain by the convertion factor:

0.37 moles H₂ x 2 moles NH₃/ 3 moles H₂= 0.246 moles NH₃ ≅ 0.25 moles NH₃

Thus, 0.25 moles of NH₃ will be obtained.

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son4ous [18]

Answer:

1 mol of water is produced in those conditions.

Explanation:

The reaction to produce water between H₂ and O₂ is this:

2H₂  +  O₂  →  2H₂O

We don't have the amount of hydrogen, so we have to think that is in excess.

Let's work with oxygen.

Ratio is 1:2

For 0.5 mole of oxygen, I will make the double of moles of water.

4 0
3 years ago
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Three samples of the same metal are weighed and their masses are found to be 44.40 g, 40.58 g, and 38.35 g. The corresponding vo
lidiya [134]

The density of a material is the mass of the material per unit volume. Here the weight of the same metal is 44.40g, 40.58g and 38.35g having volume 4.8 mL, 4.7 mL and 4.2 mL respectively. Thus the density of the metal as per the given data are, \frac{44.40}{4.8} = 9.25g/mL, \frac{40.58}{4.7} = 8.634g/mL and \frac{38.35}{4.2} = 9.130g/mL respectively.

The equation of the standard deviation is √{∑(x  - \frac{}{x})÷N}

Now the mean of the density is {(9.25 + 8.634 + 9.130)/3} = 9.004 g/mL.

The difference of the density of the 1st metal sample (9.25-9.004) = 0.246 g/mL. Squaring the value = 0.060.

The difference of the density of the 2nd metal sample (9.004-8.634) =0.37 g/mL. Squaring the value = 0.136.

The difference of the density of the 3rd metal sample (9.130-9.004) = 0.126 g/mL. Squaring the value 0.015.

The total value of the squared digits = (0.060 + 0.136 + 0.015) = 0.211. By dividing the digit by 3 we get, 0.070. The standard deviation will be \sqrt{0.070}=0.265. Thus the standard deviation of the density value is 0.265g/mL.  

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Which process will change a substance chemically? A. boiling B. melting C. burning D. evaporating
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3 years ago
When 0.0901 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. I
Alexus [3.1K]

Answer:

The heat of combustion for the unknown hydrocarbon is -29.87 kJ/mol

Explanation:

Heat capacity of the bomb calorimeter = C = 1.229 kJ/°C

Change in temperature of the bomb calorimeter = ΔT = 2.19°C

Heat absorbed by bomb calorimeter = Q

Q=C\times \Delta T

Q=1.229 kJ/^oC\times 2.19^oC=2,692 kJ

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6 0
4 years ago
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An unknown compound contains only carbon and hydrogen. Combustion analysis of the compound produces 0.2845 g of carbon dioxide a
Len [333]

Answer:

C2H5

Explanation:

As the question says, the carbon from the compound is used to form carbon dioxide and the hydrogen is used to form the water, if the analysis of the compound produces 0.2845 g of and 0.1451 g and we know the molar mass of CO2 and H2O(44 and 18 (g/mol), respectively), it is possible to calculate the number of moles of CO2 and H2O.

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Then if we multiply by two, the empirical formula is C2H5, it is because it can´t be represented by non integer numbers.

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