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likoan [24]
3 years ago
7

C). If 0.5 mole of oxygen (,) reacted with hydrogen (H2), how many mole of water (H20) was produced

Chemistry
2 answers:
Harrizon [31]3 years ago
6 0

Answer:

1.0 mol of water will be produced.

Explanation:

Step 1: Data given

Number of moles of oxygen (O2) = 0.5 moles

Step 2: The balanced equation

2H2 + O2 → 2H20

Step 3: Calculate moles of water (H20)

For 2 moles of H2 consumed, we need 1 mol of O2 to produce 2 moles of water (H2O)

For 0.5 moles of oxygen (O2) we'll have 2*0.5 = 1.0 moles of water (H20) produced

1.0 mol of water will be produced.

son4ous [18]3 years ago
4 0

Answer:

1 mol of water is produced in those conditions.

Explanation:

The reaction to produce water between H₂ and O₂ is this:

2H₂  +  O₂  →  2H₂O

We don't have the amount of hydrogen, so we have to think that is in excess.

Let's work with oxygen.

Ratio is 1:2

For 0.5 mole of oxygen, I will make the double of moles of water.

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<u>Answer:</u> The moles of water produced are 1.54 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethane = 15.42 g

Molar mass of ethane = 30.07 g/mol

Putting values in above equation, we get:

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Hence, the moles of water produced are 1.54 moles.

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