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3 years ago

How do you know how many electrons an element will gain or lose in forming an ion?

1 answer:

7 0

First the element has to be stable. One chooses the easiest way to make the element stable. for example : Al has 13 electrons and you want to make it stable, you consider the outermost electrons where in AL the are three so it is easier for Al to lose three than to gain five

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What is the most common acid and base?<br>and why?

KatRina [158]

Answer:

Acids and bases are used in most many chemical reactions in chemistry . They are responsible for most colour changes in a chemical reaction and are used to adjust the pH of chemical solutions.

Explanation:

3 0

3 years ago

Fill in the left side of this equilibrium constant equation for the reaction of nitrous acid (HNO_2) with water.

mafiozo [28]

Answer:

$Ka=\frac{[H^+][NO_2^-]}{[HNO_2]}$

Explanation:

The reaction

The reaction of nitrous acid with water is a dissociation reaction of an acid:

$HNO_2(aq) + H_2O(l) \longrightarrow H^+(aq) + NO_2^-(aq) + H_2O(l)$

$HNO_2(aq) \longrightarrow H^+(aq) + NO_2^-(aq)$

The Ka equation

$Ka=\frac{[H^+][NO_2^-]}{[HNO_2]}$

5 0

3 years ago

Read 2 more answers

For problems 2 & 3, the density of the sample is 0.9977 g/mL and the molar mass of calcium carbonate is 100.0 g/mol. 2. Calc

Alenkasestr [34]

1) Use of density formula to calculate mass of sample, M

D = M / V => M = D* V = 0.9977 g / mL * 50.00 mL = 49.885 g of sample

Realize that the sample is the solution.

2) Use ppm concentration to calculate mass of solute (calcium carbonate)

By definition, 75.0 ppm = 75.0 g of calcium carbonate / 1,000,000 g of solution.

You use that ratio to calculate the mass of calcium carbonate in 49.885 g of solution.

Mass of solute = 49.885 g of solution * [75.0 g of calcium carbonate] / [1,000,000 g of solution] =

Mass of solute = 0.00374 g of calcium carbonate

Answer: 0.00374 g of calcium carbonate

4 0

3 years ago

The average mass of a nitrogen atom is 14.006 amu from the two isotopes with the following data: 14N-14.00307 amu with 0.9963 fr

Nesterboy [21]

Answer:

d. 99.63% and 0.364%, respectively

Explanation:

The average mass of a nitrogen atom is 14.006 amu

14N-14.00307 amu with 0.9963 fractional abundance

1SN- 15.000108 amu with 0.00364 fractional abundance.

The relative abundance definition in chemistry is the percentage of a particular isotope that occurs in nature. The atomic mass listed for an element on the periodic table is an average mass of all known isotopes of that element.

In this problem, the fractional abundance has areaady been given. All we need to do now is convert them to percentage abundance.

14N-14.00307 = 0.9963* 100% = 99.63%

1SN- 15.000108 = 0.00364 * 100% = 0.364%

7 0

3 years ago

If the outside of your flask is not dry when the first mass determination is made and it is dried for the second mass determinat

svlad2 [7]

Answer:

You'll experience a grater deviation

Explanation:

<em>You'll experience a greater deviation in your measurements, meaning your measures will have a bigger difference between them, and the greater these deviations the less accurate will be the measuring.</em> This happens mainly because you're not replicating the measurement with the exact same conditions, in one of them you'll have an extra mass from the water.

I hope you find this information useful and interesting! Good luck!

8 0

3 years ago