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Sergeeva-Olga [200]
3 years ago
6

Sometimes a particle of radiation penetrates a substance and continues on its way, and sometimes it doesn't. For the particles t

hat don't make it through a substance, what happened to them? At the atomic level what part of an atom did they hit? As for the particles that weren't shielded or blocked by the material, how did they manage to get through? Also, explain why denser substances shield better than lighter substances.
Chemistry
1 answer:
Amanda [17]3 years ago
6 0

Explanation:

According to the atomic model of Rutherford, an atom has most of empty space inside the region where electrons reside.

And, nucleus is the smaller part that is, present at the center of an atom. It is solid and inside the nucleus there are  protons and neutrons are present.

  • When radiation hits a solid particle then they hit the positively charged nucleus due to the positive charge of protons. So, they tend to face a strong repulsion and then they retrace the path. As a result, they make it through the substance.
  • Now, at the atomic level they hit the nucleus of the atom that s, positively charged.
  • Particles that are not shielded or blocked by material tend to pass directly through the large empty space as in this empty space there is no repulsion because of nucleus. As a result, they tend to pass directly through the material without any disturbance.
  • Denser is a substance, larger will be its nucleus. This means that then there will be more number of protons and neutrons inside the nucleus.  Hence, there will be high positive charge on the nucleus and very less free space that will allow very less number of radiations to pass through without any disturbance.

Thus, denser substance will shield better as compared to the lighter substances.

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pashok25 [27]

When the concentrations of CO2 and H2CO3 are both horizontal lines then the rate of the forward reaction is the same as the rate of the reverse reaction.

<h3>What is rate of reaction?</h3>

The term rate of reaction refers to how fast or slow a reaction proceeds. Recall that the rate  of reaction is measured from the rate of disappearance of reactants or the rate of appearance of products.

When the [CO2] and [H2CO3 ] are both horizontal lines, the rate of the forward reaction is the same as the rate of the reverse reaction.

Let us recall that the reaction is reversible hence addition of H2CO3  will increase the concentration of H2CO3, the reverse reaction would be favored.

Learn more about rate of reaction: brainly.com/question/8592296

4 0
2 years ago
In a different experiment, the student uses a calorimeter which is perfectly insulated. She fills the calorimeter with 100.0 g o
alexdok [17]

Answer:

Explanation:

Mg + 2HCl = Mg Cl₂ + H₂

.594 g = .594 / 24.3

= .02444 mole

Heat evolved = msΔ T , m is mass of water ( solvant ) , s is specific heat of water , Δ T is rise in temperature

= 100 x 4.2 x ( 41.83 - 25 )

= 7068.6 J

.02444 mole  of Mg evolves 7068.6 J of heat

1 mole of Mg evolves 7068.6 /.02444 J

= 289222.6 J

= 289 kJ .

Molar heat enthalpy = 289 kJ .

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Ted used a balance scale to weigh a 2.233 g sample of copper sulfate. Which of these measurements made by Ted is the most accura
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What are Seismic waves?
Vikki [24]

Answer:

Seismic waves are waves of energy that travel through Earth's layers, and are a result of earthquakes, volcanic eruptions, magma movement, large landslides and large man-made explosions that give out low-frequency acoustic energy

Explanation:

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6 0
2 years ago
In acidic aqueous solution, the purple complex ion Co(NH3)5Br2+ undergoes a slow reaction in which the bromide ion is replaced b
kirill115 [55]

Answer:

A) 0.065 M is its molarity after a reaction time of 19.0 hour.

B) In 52 hours [Co(NH_3)5Br]^{2+} will react 69% of its initial concentration.

Explanation:

Co(NH_3)_5(H_2O)_3+[Co(NH_3)5Br]^{2+}(Purple)(aq)+H_2O(l)\rightarrow [Co(NH_3)_5(H_2O)]^{3+}(Pinkish-orange)(aq)+Br^-(aq)

The reaction is first order in [Co(NH_3)5Br]^{2+}:

Initial concentration of [Co(NH_3)5Br]^{2+}= [A_o]=0.100 M

a) Final concentration of [Co(NH_3)5Br]^{2+} after 19.0 hours= [A]

t = 19.0 hour = 19.0 × 3600 seconds ( 1 hour = 3600 seconds)

Rate constant of the reaction = k = 6.3\times 10^{-6} s^{-1}

The integrated law of first order kinetic is given as:

[A]=[A_o]\times e^{-kt}

[A]=0.100 M\times e^{-6.3\times 10^{-6} s^{-1}\times 19.0\times 3600 s}

[A]=0.065 M

0.065 M is its molarity after a reaction time of 19.0 h.

b)

Initial concentration of [Co(NH_3)5Br]^{2+}= [A_o]=x

Final concentration of [Co(NH_3)5Br]^{2+} after t = [A]=(100\%-69\%) x=31\%x=0.31x

Rate constant of the reaction = k = 6.3\times 10^{-6} s^{-1}

The integrated law of first order kinetic is given as:

[A]=[A_o]\times e^{-kt}

0.31x=x\times e^{-6.3\times 10^{-6} s^{-1}\t}

t = 185,902.06 s = \frac{185,902.06 }{3600} hour = 51.64 hours ≈ 52 hours

In 52 hours [Co(NH_3)5Br]^{2+} will react 69% of its initial concentration.

6 0
3 years ago
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