No. If you plug in the points, you have 2=5(4). 2=20 is not true, so it does not satisfy it
Answer:
15.5 inches
Step-by-step explanation:
- Length of rectangle = 22 inches
- Perimeter = 75 inches
To calculate : Width of the rectangle.
★ Perimeter of rectangle = 2( l + w )
→ 75 = 2(22 + w)
→ 75 = 44 + 2w
→ 75 – 44 = 2w
→ 31 = 2w
→ 31 ÷ 2 = w
→ <u>1</u><u>5</u><u>.</u><u>5</u><u> </u><u>inches</u><u> </u><u>=</u><u> </u><u>Width</u>
Therefore, width of the rectangle is 15.5 inches.
Answer:
is it 22.
Step-by-step explanation:
is it?
By taking the quotients between the areas, we see that:
<h3>
How to find the probabilities?</h3>
First we need to find the areas of the 3 shapes.
For the triangle, the area is:
T = 3*5/2 = 7.5
For the blue square, the area is:
S = 3*3 = 9
For the rectangle, the area is:
R = 10*6 = 60
Now, what is the probability that a random point lies on the triangle or in the square?
It is equal to the quotient between the areas of the two shapes and the total area of the rectangle, this is:
P= (7.5 + 9)/60 = 0.275
b) The area of the rectangle that is not the square is:
A = 60 - 9 = 51
Then the probability of not landing on the square is:
P' = 51/60 = 0.85
If you want to learn more about probability:
brainly.com/question/25870256
#SPJ1
Answer:
where is the question?
Step-by-step explanation:
