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mixas84 [53]
3 years ago
7

Compare the box plots for two data sets.

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0

Answer: The median for set a is greater

Step-by-step explanation:

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Four students are working in a group and are asked to find the length of BC. Which two students set up the problem correctly? Mo
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The best and the most correct answer among the choices provided by the question is the first choice. The two students that set up the problem correctly is <span> Moe: x = (5 - 1)2 + (1 - 4)2 and Jimmy: x2 = 32 + 42.</span> I hope my answer has come to your help. God bless and have a nice day ahead!
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3 years ago
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The vertices of a right triangle are (–5, –2), (–1, –6), and (–5, y).
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4 0
3 years ago
If sin A = 3/8, find the value of cosec A - sec A.​
alexira [117]

Answer:

\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

Step by step explanation:

\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies  1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\

\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}

\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

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2 years ago
What number needs to be added to 4 and 7 so that the ratio of
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a.

Step-by-step explanation:

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1/3

Step-by-step explanation:

there is a total of 3 guitar picks

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