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3 years ago

Find the point that lies on the line described by the equation below. y - 8 = - 3 (x-6)

Mathematics

1 answer:

ohaa [14]3 years ago

4 0

Answer:

B. (6, 8)

Step-by-step explanation:

To figure this out, you can plug in the coordinates to see if you get matching answers. Since you believe answer "B," is correct, we can check:

y - 8 = -3(x - 6)

8 - 8 = -3(6 - 6)

0 = -3(0)

0 = 0

<u>Since the answers match, that makes answer "B," correct.</u>

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Answer:

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Step-by-step explanation:

The tangent line has length "x + 8"

The secant line has length "x + 6 + 5", where

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Now,

the secant-tangent theorem tells us that square of the tangent line is equal to the outer segment of secant line multiplied by length of whole secant line.

So, we can say:

$(x+8)^2 = (x+6)(x+6+5)$

We can solve for x shown below:

$(x+8)^2 = (x+6)(x+6+5)\\(x+8)^2=(x+6)(x+11)\\x^2+16x+64=x^2+17x+66\\17x-16x=64-66\\x=-2$

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3 years ago

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$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

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3 years ago

Find the point that lies on the line described by the equation below. y - 8 = - 3 (x-6)​

Find the point that lies on the line described by the equation below. y - 8 = - 3 (x-6)