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mestny [16]
3 years ago
15

During a fourth of July celebration, a cannon is fired upwards from Fort Ontario. The height, h, in feet, of the cannonball abov

e sea level at any given time, t, in seconds, can be determined by the formula h = -16t2 + 120t + 200. Find the height, in feet, of the cannonball above sea level 5 seconds after the cannon is fired.
Mathematics
2 answers:
ANEK [815]3 years ago
7 0

Answer:

400 feet

Step-by-step explanation:

We just need to find h when t = 5. To do so, we can plug t = 5 into the function, which would be:

h = -16t² + 120t + 200

  = -16 * 5² + 120 * 5 + 200

  = -400 + 600 + 200 = 400 feet

Snowcat [4.5K]3 years ago
3 0

Answer:

h = 400 feet

Step-by-step explanation:

given t = 5 seconds

h = -16t² + 120t + 200

just substitute t = 5

h = -16(5)² + 120(5) + 200

h = 400 feet

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when is 9 = 15.2 - 0.537x

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Could someone help me rnnn?
GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola:  y=3x^2-4

Step-by-step explanation:

Given:

  • y-intercept of parabola: -4
  • parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola:  y=a(x-h)^2+k

(where (h, k) is the vertex and a is some constant)

Substitute point (0, -4) into the equation:

\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}

Substitute point (-2, 8) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}

Substitute point (1, -1) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}

Equate to find h:

\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}

Substitute found value of h into one of the equations to find a:

\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}

Substitute found values of h and a to find k:

\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}

Therefore, the equation of the parabola in vertex form is:

\implies y=3(x-0)^2-4=3x^2-4

So the vertex of the parabola is (0, -4)

5 0
2 years ago
Read 2 more answers
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