Do you have a formula sheet or was one provided to you
the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.
The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.
In terms of hyperbola, F1F2=2c, c=20.
The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.
Use formula c^2=a^2+b^2c
2
=a
2
+b
2
to find b:
\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}
(20)
2
=(18)
2
+b
2
,
b
2
=400−324=76
.
The branches of hyperbola go in y-direction, so the equation of hyperbola is
\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1
b
2
y
2
−
a
2
x
2
=1 .
Substitute a and b:
\dfrac{y^2}{76}- \dfrac{x^2}{324}=1
76
y
2
−
324
x
2
=1 .
9514 1404 393
Answer:
x ∈ (-∞, 9) U (-1, ∞)
Step-by-step explanation:
Get the absolute value by itself. Do that by multiplying by 4.
|3x +15| > 12
This resolves to two cases:
<u>3x +15 > 12</u>
x +5 > 4 . . . . divide by 3
x > -1 . . . . . . .subtract 5
<u>-(3x +15) > 12</u>
x +5 < -4 . . . . divide by -3
x < -9 . . . . . . . subtract 5
Then the solution in interval notation is ...
x ∈ (-∞, 9) U (-1, ∞)
3/4-3=43 Thsts the answer hopes it help
Answer:
Step-by-step explanation:
2n+5=35
2n=35-5
2n=30
n=15
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