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3 years ago

I need this for my notes so i can know what to do. What is the length of AC? And Length of AB?

Mathematics

2 answers:

andre [41]3 years ago

8 0

Answer:

AC 5

AB = 3

Step-by-step explanation:

AC = distance between the points

C-A = 3 - -2 = 3+2 = 5

The distance is 5

AB = distance between the points

B-A = 1 - -2 = 1+2 = 3

The distance is 3

Andru [333]3 years ago

7 0

Answer:

AC = 5

AB = 3

Step-by-step explanation:

AC:

3 - X = -2

3 - 5 = -2

AB:

1 - X = -2

1 - 3 = -2

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If it takes 5 minutes for 5 machines to make 5 objects, then how long would it take for 100 machines to make 100 objects?

miss Akunina [59]

1 machine 5 min. 1 object
100 machine x min. 100 object

so than from this result that for 100 machine to make 100 objects need 5 minutes

hope this will help you

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3 years ago

WILL MARK BRAINLIEST! 30 PTS-----An equilateral triangle has what type of symmetry?

Ghella [55]

Answer:

A. line symmetry only.

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3 years ago

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3 years ago

Read 2 more answers

Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1

Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

$P(x=r)=^nC_rp^rq^{n-r}$

(a) Exactly two will be drunken drivers.

$P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}$

$P(x=2)=66(0.2)^{2}(0.8)^{10}$

$P(x=2)=\approx 0.28347$

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

$P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)$

$P(x=3\text{ or }x=4)=P(x=3)+P(x=4)$

Using binomial we get

$P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}$

$P(x=3\text{ or }x=4)=0.236223+0.132876$

$P(x=3\text{ or }x=4)\approx 0.369099$

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

$P(x\geq 7)=1-P(x$

$P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]$

$P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]$

$P(x\leq 7)=1-[0.9961]$

$P(x\leq 7)=0.0039$

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

$P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)$

$P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315$

$P(x\leq 5)=0.9806$

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0

3 years ago

Kamilah’s weight has tripled since her first birthday. If w represents the amount Kamilah weighed on her first birthday, write a

S_A_V [24]

Answer:

3*w

Step-by-step explanation:

Kamilah now weighs the triple of what she weighed on her first birthday. That means we need to multiply the first weight by 3. As the first weight is w, she now weighs 3*w.

Another possible expression is to sum 3 times w, that is w + w + w (it's equal to 3*w).

8 0

3 years ago