EF is a median of trapezoid ABCD. The length of AB is 12, and the length of CD is 18. The length of BF is 4. What is the length
of FC?
1 answer:
Answer:
Step-by-step explanation:
The diagram representing the trapezoid is shown in the attached photo. The median EF is a line segment that is half way between the 2 bases. The length of the median is the average of the two bases. Therefore,
EF = (12 + 18)/2 = 15
Two similar trapezoids are formed. They are ABFE and EFCD
By comparing both trapezoids, it means that
4/15 = FC/18
Cross multiplying, it becomes
4 × 18 = 15FC
72 = 15FC
FC = 72/15
FC = 4.8
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