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Hoochie [10]
3 years ago
9

La mamá del profesor Ernesto tiene una bolsa con 3/4 kilogramos de arroz y guiso 2/3 de su contenido Que fracción de un kilogram

o utilizo para cocinar
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer: ella usó (1/2) kg de arroz para cocinar.

Step-by-step explanation:

La madre de Ernesto tenía una bolsa con 3/4 kg de arroz.

Sabemos que uso 2/3 de esa cantidad para hacer un guiso.

Entonces ella usó 2/3 de 3/4 kilogramos de arroz.

Entonces ella usó:

(2/3)*(3/4) kg de arroz.

Recordemos que esto se puede escribir como el producto entre los numeradores dividido por el producto de los denominadores:

(2*3)/(3*4) kg de arroz.

(6/12) kg de arroz

(1/2) kg de arroz.

Esto significa que ella usó (1/2) kg de arroz para cocinar.

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Step-by-step explanation:

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The ratio of boys to girls at the beach cleanup was 7:8. If there were 42 boys, how many girls were there?
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Dustin loves to cook with fresh herbs. So, he decides to plant 8 different herbs and keep the small pots on his kitchen windowsi
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3 years ago
The density of salt is 80 pounds per cubic foot (lb/ft3). 1 pound (lb) is approximately 0.4536 kilogram (kg). 1 cubic foot (ft3)
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Step-by-step explanation:

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then we can write:

1 = (0.4536kg)/(0.0283 m^3)*(1ft^3/lb)

we can multiply our equation by this, and it wont be affected, then we have:

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6 0
3 years ago
A 90% confidence interval for the mean height of students
Westkost [7]

Answer:

ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635

And the best answer on this case would be:

b) m = 4.635

Step-by-step explanation:

Let X the random variable of interest and we know that the confidence interval for the population mean \mu is given by this formula:

\bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}

The confidence level on this case is 0.9 and the significance \alpha=1-0.9=0.1

The confidence interval calculated on this case is 60.128 \leq \mu \leq 69.397

The margin of error for this confidence interval is given by:

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ME = \frac{Upper -Lower}{2}

Where Upper and Lower represent the bounds for the confidence interval calculated and replacing we got:

ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635

And the best answer on this case would be:

b) m = 4.635

4 0
3 years ago
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