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3 years ago

Lisa used the rule "Red, Yellow, Yellow, Yellow" to make a bracelet with a repeating pattern. She

Mathematics

1 answer:

konstantin123 [22]3 years ago

8 0

Answer:

28 beads were used to make the bracelet. 7 beads were not yellow.

Step-by-step explanation:

3/4 beads used to make the bracelet are yellow

If 21 beads are 3/4 of the bracelet and yellow

1/3 of the 21 beads would be 1/4 of the bracelet

7 beads are 1/3 of 21 beads

7 × 4 = 28 beads

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Susan has 4 times as much money as her sister .If Susan has ten dollars ,how much money does her sister have.

vredina [299]

$2.50 of money because 4 times 2.5 = 10

8 0

3 years ago

What value of x makes the equation true 4x = 32?

pochemuha

Answer:

$x=8$

Step-by-step explanation:

$4x=32$

$4\times x =32$

Divide both sides by 4:

$\frac{4\times x}{4}=\frac{32}{4}$

$x=8$

5 0

4 years ago

Read 2 more answers

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$