F(x)=x^2 what is g(x)?

HELP PLEASE ILL GIVE BRAINLEST IF U HELP QUICK

Cloud [144]

$\qquad\qquad\displaystyle \huge Answer$

Let's check if (3 , 6) is the point of intersection of the given lines ~

$\qquad \displaystyle \: y = 4x - 2$

and

$\qquad \displaystyle \: y = \frac{1}{2} x + 5$

If the point is the point of intersection of these two lines, then it should satisfy both the equations ~

let's try each of them, using x coordinate of point.

$\qquad \displaystyle \: y = 4(3) - 2$

$\qquad \displaystyle \: y = 12 - 2$

$\qquad \displaystyle \: y = 10$

So, the point didn't actually satisfy one of the equation. hence we can infer that the given statement is wrong.

3 0

2 years ago

Which of the follwoing are solutions to the inequality -7x+14>-3x-6

gogolik [260]

Greetings! let’s solve this shall we?

So,
7x + 14 > -3x - 6

14 > -3x - 6 + 7x

14 > 4x - 6

20 > 4x

5 > x

4 0

2 years ago

Answer this question.<br><br> You get a thank you and 5 stars if it's the correct answer.

Elena L [17]

Answer:

w=5

x=7

y=6

z=12

Step-by-step explanation:

hope this helps you

4 0

3 years ago

Read 2 more answers

SHOE COLLECTION: Marquise, Bron'Tavious, and JayDarius each have a shoe collection of Nike Air Vapor Max shoes. Marquise has two

Natasha_Volkova [10]

Answer:

(a) The number of shoes that Marquise has is 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has is 20 pairs of shoes

(c) The number of pairs of shoes that JayDarius has is 35 pairs of shoes

Step-by-step explanation:

The given information are;

The number of shoes that Marquise has = 2 × The number of pairs of shoes that Bron'Tavious

The number of pairs of shoes that JayDarius has = The number of pairs of shoes that Bron'Tavious + 15

The total number of pairs of shoes they have all together = 95 pairs of shoes

Let the number of pairs of shoes that Bron'Tavious has = X. Therefore, we have;

The number of shoes that Marquise has = 2 × X

The number of pairs of shoes that JayDarius has = X + 15

The total number of pairs of shoes they have all together = X + X + 15 + 2 × X = 95

X + X + 15 + 2 × X = 95

4 × X + 15 = 95

4 × X = 95 - 15 = 80

X = 80/4 = 20

∴ X = 20

(a) The number of shoes that Marquise has = 2 × X = 2 × 20 = 40

The number of shoes that Marquise has = 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has = X = 20

The number of pairs of shoes that Bron'Tavious has = 20 pairs of shoes

(c) The number of pairs of shoes that JayDarius has = X + 15 = 20 + 15 = 35

The number of pairs of shoes that JayDarius has = 35 pairs of shoes.

5 0

3 years ago

Willard Hudson took out a simple interest loan of $6,000.00 at 10 percent interest for 24 months. His monthly payment is $276.60

bezimeni [28]

9514 1404 393

Answer:

a) $42.35

b) $5124.56

c) $407.44

Step-by-step explanation:

a) The interest due is that for one month on the remaining balance:

I = Prt

I = $5082.21·0.10·1/12 = $42.35

__

b) The final payment is ...

$5082.21 +42.35 = $5124.56

__

c) Had Hudson continued paying, he would have paid ...

20·$276.60 = $5532.00

So, he saved ...

$5232.00 -5124.56 = $407.44

3 0

3 years ago