The two sets of parametric equations for the rectangular equation are;
- If x=t+6 then y= t²-7t-42.
- If x=7t then y= 49t² - 133t +36.
<h3>What are the parametric equations from the rectangular equation?</h3>
It follows from the task content that the parametric equations can be determined as follows;
By substituting the x= t+6 into the rectangular equation; we have;
y = (t+6-6)²-7(t+6)
y = t²-7t-42.
By substituting the x= 7t into the rectangular equation; we have;
y = (7t-6)² -7(7t)
y = 49t² - 84t +36 - 49t
y = 49t² - 133t +36.
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There is only one R in the bag
So the probability would be 1/6
1/6 as a decimal is 0.16
Thus, your answer would be option D
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Answer:
The distance cover by Bell is 8 miles .
Step-by-step explanation:
Given as :
The distance cover by Mike = The distance cover by Pete = D miles
Let The distance cover by Bell = d miles
The distance cover by Mike = 15 miles + distance cover by Bell
i.e D = 15 + d ............1
Again
The distance cover by Pete = three time distance cover by Bell - 1 miles
i.e D = 3 × B - 1
Or, D = 3 d - 1 ............2
Now, Solving equation 1 and 2
So, 15 + d = 3 d - 1
Or, 3 d - d = 15 + 1
Or, 2 d = 16
∴ d = 
i.e d = 8 miles
So,The distance cover by Bell = d = 8 miles
Hence, The distance cover by Bell is 8 miles . Answer
3. The original sequence
TAC - CGC - TTA - CGT - CTG - ATC - GCT
codes for
tyr - arg - leu - arg - leu - ile - ala
while the mutated sequence codes for
TAC - CGC - TTA - TTA - TTA - CGT - G<u>CT</u> - <u>G</u>CT - ATC - GCT
tyr - arg - leu - leu - leu - arg - <u>ala</u> - ala - ile - ala
There are several frameshift mutations involved here:
• the first inserts 6 bases (TTA - TTA)
• the second inserts 1 base (G) before the CTG triplet (underlined)
• the third inserts 2 bases (CT) after the CTG triplet
4. The original sequence is the same as before. The mutated sequence
TAC - CGC - TAA - TTA - TTA - CGT - G<u>CT</u> - <u>G</u>CT - ATC - GCT
codes for
tyr - arg - STOP - leu - leu - arg - ala - ala - ile - ala
Then
• there is a (nonsense) point mutation that swaps T for A in the original TTA triplet (nonsense since it produces a stop codon that would halt replication/expression)
• there is a frameshift mutation that inserts 3 bases (TTA)
as well as two other frameshift mutations that also occurred in the previous part.
