Answer:
1 35
Explanation:
* There is a little typo in printf. It should be "\n".
Initially, the value of the first is 1, and the value of the second is 2. Then, do_something(&second, first) is called. The value of the <em>first</em> will still be 1. However, there is a call by reference for <em>second </em>variable. That means the change made by the function <em>do_something</em> will affect the value of the <em>second</em> variable.
When you look at the calculation inside the <em>do_something</em> function, you may see that value of the <em>second</em> will be 35.
Answer:
Explanation:
The following code is written in Python. It creates a variable that detects the current time. Then it loops through a range of numbers and chooses the last random number after 2 seconds. Finally, it prints that number to the screen. This function can be called countless times depending on the number of state lottery numbers needed.
import random
import time
start_time = time.time()
while time.time() - start_time < 2:
lottery_number = random.randint(0, 48)
print(lottery_number)
<u>Answer:</u>
The correct answer option is D. set the switch to the highest range and then move it to a range that gives the most accurate reading.
<u>Explanation:</u>
When measuring an unknown voltage with an analog VOM, one should set the meter to the highest range and then move it to a range that gives the most accurate reading.
The reason being that the analog meters indicate the measurement of voltage by moving a needle across a physical card by printing numbers on it.
So in case the voltage is nearly 100 times the full range to which the meter is set, then its needle will try move to a position which will be 100 times the highest number on the meter.
Answer:
Explanation:
Required
Which returns smallest integer greater than or equal to 7.3
i.e.
When executed, the result of each instruction is:
-- This returns the smallest integer greater than 7.3
--- This returns the smallest integer less than 7.3
<em></em>
<em> --- there is no such thing as larger() in python</em>
--- This rounds 7.3 to the nearest integer
From the above result,
8 is the smallest integer greater than or equal to 7.3
i.e.
Hence:
is correct
Answer:
public class num6 {
public static void main(String[] args) {
int n = 4;
for(int i = 1; i <= n; ++i) {
for(int j = 1; j <= i; ++j) {
System.out.print("* ");
}
System.out.println();
}
}
}
Explanation:
This solution is implemented in Java
Two for loops are required for this (an inner nd outer for loop).
The innner and outer for loops can be seen as implementing rows and columns (so on the first 'row' i=1, so a single star is printed, on the second row, i =2, two stars are printed and so on, all on seperate lines)
