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marin [14]
3 years ago
8

Which formula can be used to find the ninth term of a geometric sequence where the first term is 8 and the common ratio is -3

Mathematics
1 answer:
telo118 [61]3 years ago
3 0
For a geometric sequence with a first term of "a" and a common ratio of "r", the n-th term is
.. an = a*r^(n-1)

For this problem, you have a = 8, r = -3, and n = 9. Filling these values into the formula gives
.. a9 = 8*(-3)^(9-1)
.. a9 = 8*(-3)^8

_____
a9 = 52,488
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Please help me!<br><br> Thank you
fgiga [73]

The required measures of the angle are given as,
∠JKL = 72°      ∠MLK = 108°      ∠JMK = 36°
∠MJL = 54°       ∠KNL = 90°

Given that.
The measure of the rhombus is given, we have to determine the measure of the angles,

<h3>What is angle?</h3>

orientation of one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as angle.

Here,
∠JKL= 2 × ∠JKM  = 72°
∠MLK = 180 - 2 × ∠JKM =  108°
∠JMK = ∠JKM = 36°
∠MJL = ∠MLK/2 =  54°
The diagonal of the rhombus bisect each other at an angle of 90°
So,
∠KNL = 90°

Thus, all the measure of the angles is shown above.

Learn more about Angles here:
brainly.com/question/13954458

#SPJ1

7 0
1 year ago
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suter [353]

Answer:

d = 16 / 3.14

Step-by-step explanation:

The diameter is equal to the circumference divided by 3.14.

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