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lesantik [10]
2 years ago
12

Consider the equation and its solution. Negative 15 (x minus box) = 25. Negative 15 x + 30 = 25. Negative 15 x = negative 5. x =

one-third. What number should be in the empty box? Negative 30 Negative 2 2 30
Mathematics
2 answers:
Romashka-Z-Leto [24]2 years ago
6 0

Answer:

-2

Step-by-step explanation:

Solnce55 [7]2 years ago
4 0

Answer:

  -2

Step-by-step explanation:

Between the first two steps we see ...

  15(x-\boxed{^})=25\\\\15x+30=25

Applying the distributive property to the first equation and comparing to the second, we see that ...

  -15\boxed{^}=30\\\\\boxed{^}=\dfrac{30}{-15}=-2

The number in the box should be -2.

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natali 33 [55]
No because the exact opposite of -3 would be 3.
7 0
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Item 12
svet-max [94.6K]
<span>If the width is w, and the length is w+10, then the perimeter is

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4 0
3 years ago
Need help on these !! 13 and 14! Please!!
katen-ka-za [31]

Question # 13

Answer:

The required equation for the given function is <em>y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.</em>

<em>Step-by-step explanation: </em>

As the general sine function is given by

y=asin(bx+c)+d.......[A]

  • amplitude = a
  • period = 2π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • amplitude = a = 4
  • period = 4π
  • phase shift = -4π/3
  • Vertical shift = d = -2

As  

period = 2π ÷ b  

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2  

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b  

c = b × 4π/3  

c = 1/2 × 4π/3  

c = 4π/6  

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,  

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

y=asin(bx+c)+d

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2            

<em>Note: The graph is also shown in attached diagram.</em>

                                             Question # 14

<em>Answer:</em>

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

<em>Step-by-step explanation: </em>

As the general cotangent function is given by

y=acot(bx+c)+d.......[A]

  • amplitude = a
  • period = π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • period = π
  • phase shift = -π/3
  • Vertical shift = d = 2

As  

period = π ÷ b  

b = π/period

b = π/π ∵ period = 4π

b = 1  

Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b  

c = b × π/3  

c = 1 × π/3  

c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and   c = π/3 in Equation [A] would bring us the required equation for the given function.

y=acot(bx+c)+d

y = cot(x+π/3)+2

<em>Note: The graph is also shown in attached diagram.</em>

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

7 0
3 years ago
Is 226.08cm to the third power the correct response?
drek231 [11]
Surface Area of a cylinder 2(π•r²)+(2π•r)•h

So

If the diameter is 8 then the radius is 4. the height is 5.

so you have, 2(3.14•4²)+(2•3.14•4)•5

solve. PEMDAS
Parentheses & Exponents first.
2(3.14•16)+(2•3.14•4)•5
2(50.24)+(6.28•4)•5
2(50.24)+(25.12)•5
Multiplication & Division second (left to right)
100.48+125.6
Add & Subtract (left to right)
226.08cm

5 0
3 years ago
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