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Archy [21]
3 years ago
15

The diameter of a sphere is 2 ft. What is the sphere's volume? Round to the nearest tenth.

Mathematics
1 answer:
pychu [463]3 years ago
7 0

Answer:

4.19 ft ^3 or A.

Step-by-step explanation:

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What is the range of g?
Alexandra [31]

Answer:

  [-4, 9]

Step-by-step explanation:

The range is the vertical extent of the relation.

__

The minimum value of g is marked by the solid dot at (x, y) = (4, -4). That minimum is -4.

The maximum value of g is the peak at (x, y) = (-2, 9). That maximum is 9.

The function is continuous between these values, so the range includes all values between -4 and +9, inclusive.

  range: [-4, 9]

3 0
3 years ago
Assessment started: undefined. Item 1 What is the median of this data set? {11, 13, 13, 14, 14, 16, 18, 23, 24} Enter your answe
Lady_Fox [76]

{11, 13, 13, 14, 14, 16, 18, 23, 24}

  • mode: 13, 14
  • median : 14
  • minimum : 11
  • maximum : 24
  • interquartile range : 7.5
  • total numbers : 9
3 0
3 years ago
Read 2 more answers
Pls help me before I have another mental breakdown
Lyrx [107]

Answer:

a) fog(x) = (x-2)⁴ +4

b) (g o f) (x) = x⁴ + 2

c) hog(x) = \sqrt{x-2}

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the function

f(x) = x⁴+4 , g(x) = x-2 , h(x) = √x

f o g (x) = f(g(x))

           = f(x-2)

         = (x-2)⁴ +4  (∵ f(x) = x⁴ +4))

fog(x) = (x-2)⁴ +4

<u><em>Step(ii):-</em></u>

(g o f) (x)  = g(f(x))

              = g(x⁴ +4)

             =  x⁴ +4 -2   ( ∵ g(x) = x-2)

            = x⁴ + 2

(g o f) (x) = x⁴ + 2

<u><em>Step(iii)</em></u>:-

hog(x) = h(g(x))

         = h(x-2)

         =  \sqrt{x-2}    

 hog(x) = \sqrt{x-2}

3 0
3 years ago
How do you do this?
Oduvanchick [21]

Answer:

∠RQS=72 ∠SQT=83

Step-by-step explanation:

4x-20+3x+14=155

7x-6=155

7x=161

x=23

∠RQS=23*4-20=92-20=72

∠SQT=155-72=83

5 0
3 years ago
The following formula is for the area, A, of the curved surface area of a cone. A = pie x r x l, where r is the radius and l is
ki77a [65]
It is Pi x r x l plus Pi x r^2
5 0
3 years ago
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